The pressure drop in pascal is 3.824*10^4 Pascals.
To find the answer, we need to know about the Poiseuille's formula.
<h3>How to find the pressure drop in pascal?</h3>
- We have the Poiseuille's formula,
- where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
- By substituting values and rearranging we will get the pressure drop as,
Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.
Learn more about the Poiseuille's formula here:
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1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):
Rearranging the equation, we can write
In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is
2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:
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Explanation:hope that helps
The correct answer is:
Let's see why.
1 amu corresponds to the mass of the proton, which is:
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
Now we can convert it into electronvolts:
So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
Answer: all of the above and yes
hope thsi helps