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DENIUS [597]
3 years ago
7

Heat energy is:

Physics
1 answer:
Archy [21]3 years ago
6 0
I claim that it's d moving electrons.
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Differentiate conductors and insulators with the help of suitable examples
andrew-mc [135]

Answer:

Any material that keeps energy such as electricity, heat, or cold from easily transferring through is an insulator

A conductor is a material which contains movable electric charges.

3 0
2 years ago
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What will be the ratio of distances between the two charges of each pair of charges (1µC, 2µC) and (2µC, -3uC) so that force her
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Answer: Anurag Mishra - Problems in Physics - Electricity and Magnetism ... Between two infinitely long wires having linear charge densities}. and -].·there are two points A ... the ratio of the electric force between them to t:-:c grav:tadonal force between them? (a) 10 8 ... d between the first two charges on the straight line at a distance

Explanation:

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3 years ago
Stella is driving down a steep hill. she should keep her car __________ to help _________.
Softa [21]

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

8 0
2 years ago
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance
FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

6 0
2 years ago
Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have 430 and 610 turns, respectively. A
KIM [24]

Answer

given,

Two solenoids A and B

Number of turn

Na = 430 turns          Nb = 610 turns

Current = 2.80 A

Average flux through  A  = 300 μWb

Average of flux through B = 90.0  μ Wb

a) L = \dfrac{N \phi}{I}

   L = \dfrac{610\times 90 \times 10^{-6}}{2.80}

   L =19.6 mH

b) inductance of A

   L = \dfrac{N_A \phi_A}{I_A}

   L = \dfrac{430\times 300 \times 10^{-6}}{2.80}

   L =46 mH

c) magnitude of the emf

    \epsilon_B = -L_B\dfrac{dI}{dT}

    \epsilon_B = -(19.6\times 10^{-3})(0.5)

    \epsilon_B = -9.8\times 10^{-3}\ V

    \epsilon_B = -9.8\ mV

7 0
3 years ago
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