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anyanavicka [17]
3 years ago
5

Mutations in certain genes of bacteria cause them to be resistant to powerful antibiotics. What type of mutation is this for the

bacteria?
1.beneficial
2.harmful
3.neutral
4.both beneficial and harmful
Chemistry
2 answers:
koban [17]3 years ago
8 0
1. beneficial. if the bactiria is resistant to something that could possibly harm them then its a good thing for the bacteria them
iren [92.7K]3 years ago
7 0

Answer:

4.both beneficial and harmful

Explanation:

Mutations that occur in bacteria that make them immune to antibiotic action can be a beneficial or harmful mutation, it depends on whether you are referring to the bacteria or to humans.

The mutation is beneficial to the bacterium because with the mutation it becomes immune to the antibiotic reaction, achieves resistance and becomes an "unbeatable" bacterium, so the mutation has a huge benefit for the bacterium because it allows it to survive and continue its life. metabolism normally.  

On the other hand, this mutation is extremely harmful to humans, because the antibiotic is what we have to fight bacteria and get rid of infections that can cause us many problems. For this reason, the mutation that makes bacteria resistant to antibiotics is highly harmful to humans.

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The reaction where sodium (Na) reacts with water to produce hydrogen gas is a type of reaction.
Kay [80]

Answer:

In what way and in what form does sodium react with water? A colourless solution is formed, consisting of strongly alkalic sodium hydroxide (caustic soda) and hydrogen gas. This is an exothermic reaction.

3 0
3 years ago
A chemist must prepare 0.200 L of aqueous silver nitrate working solution. He'll do this by pouring out some aqueous silver nitr
jeyben [28]

A chemist must prepare 0.200 L of 1.00 M aqueous silver nitrate working solution. He'll do this by pouring out 1.82 mol/L aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the silver nitrate stock solution should the chemist pour out?

Answer: 0.110 L

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock silver nitrate solution = 1.82 M

V_1 = volume of stock silver nitrate solution = ?  

M_1 = molarity of diluted silver nitrate solution = 1.00 M

V_1 = volume of diluted silver nitrate solution = 0.200 L

Putting in the values we get:

1.82M\times V_1=1.00M\times 0.200L

V_1=0.110L

Therefore, volume of silver nitrate stock solution required is 0.110 L

3 0
3 years ago
What mass of chromium would be produced from the reaction of 57.0 g of potassium with 199 g of chromium(II) bromide according to
fredd [130]

Answer:

Mass of Chromium produced = 37.91 grams

Explanation:

2K + CrBr₂  →  2KBr + Cr

2mole     1 mole                1 mole

mass of Potassium = 57.0 grams

molar mass of Potassium = 39.1 g/mol

no of moles of Potassium = 57.0 / 39.1 = 1.458 moles

mass of CrBr₂= 199 grams

molar mass of CrBr₂ = 211.8 gram/mole

no of moles of CrBr₂ = 199 / 211.8 = 0.939 mole

From chemical equation

1 mole of CrBr₂ = 2 moles of K

∴ 0.939 moles of CrBr₂ = ?

   ⇒ 0.939 x 2/1 = 1.878 moles of K

1.878 moles of K is needed, but there is 1.458 moles of K. So, Potassium is completed first during the reaction . Hence, Potassium is limiting reagent. and CrBr₂ is excess reagent .

From chemical equation

2 moles of K = 1 mole of Cr

∴ 1.458 moles of K = ?

   ⇒ 1.458 x 1/ 2 = 0.729 moles of Cr

no of moles of Cr formed = 0.729 moles

molar mass of Cr = 52.0 g/mol

mass of one mole of Cr = 52.0 grams

mass of 0.729 moles of Cr = 52.0 x 0.729 = 37.908 grams

mass of Chromium produced = 37.91 grams

6 0
3 years ago
Calculate the molarity (M) of a solution containing 49.0 grams of H3PO4 in 500 mL of solution.
vlada-n [284]

Answer

The molarity (M) of the H3PO4 solution = 1.0 M

Explanation

Given:

Mass of H3PO4 = 49.0 grams

Volume of the solution = 500 mL = 500/1000 = 0.5 L

What to find:

The molarity (M) of the H3PO4 solution.

Step-by-step solution:

Step 1: Convert 49.0 grams H3PO4 to moles using the mole formula.

Mole=\frac{Mass}{Molar\text{ }mass}

The molar mass of H3PO4 = 97.994 g/mol

So,

Mole=\frac{49.0\text{ }g}{97.994\text{ }g\text{/}mol}=0.50\text{ }mol

Step 2: Calculate the molarity of the solution using the molarity formula.

Molarity=\frac{Mole}{Volume\text{ }in\text{ }L}

Putting mole = 0.50 mol and volume = 0.50L into the formula, we have;

Molarity=\frac{0.50mol}{0.50L}=1.0\text{ }M

The molarity (M) of the H3PO4 solution = 1.0 M

5 0
1 year ago
How many moles of nitrogen gas are present in a 28.9 dm3 temperature of 55.0 °C and a pressure of 144 kPa?
jeka57 [31]

Given :

Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .

Volume of container, V = 28.9 dm³ = 0.0289 m³ .

Pressure, P = 144 kPa = 144000 Pa .

To Find :

Number of moles of nitrogen  gas.

Solution :

We know, by ideal gas equation :

PV = nRT  ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .

n = \dfrac{PV}{RT}\\\\n = \dfrac{144000\times 0.0289}{8.31 \times 328} \ moles\\\\n = \dfrac{4161.6}{2725.68}\\\\n = 1.53 \ moles

Therefore, number of moles of nitrogen gas is 1.53 moles.

8 0
3 years ago
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