1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anyanavicka [17]
3 years ago
5

Mutations in certain genes of bacteria cause them to be resistant to powerful antibiotics. What type of mutation is this for the

bacteria?
1.beneficial
2.harmful
3.neutral
4.both beneficial and harmful
Chemistry
2 answers:
koban [17]3 years ago
8 0
1. beneficial. if the bactiria is resistant to something that could possibly harm them then its a good thing for the bacteria them
iren [92.7K]3 years ago
7 0

Answer:

4.both beneficial and harmful

Explanation:

Mutations that occur in bacteria that make them immune to antibiotic action can be a beneficial or harmful mutation, it depends on whether you are referring to the bacteria or to humans.

The mutation is beneficial to the bacterium because with the mutation it becomes immune to the antibiotic reaction, achieves resistance and becomes an "unbeatable" bacterium, so the mutation has a huge benefit for the bacterium because it allows it to survive and continue its life. metabolism normally.  

On the other hand, this mutation is extremely harmful to humans, because the antibiotic is what we have to fight bacteria and get rid of infections that can cause us many problems. For this reason, the mutation that makes bacteria resistant to antibiotics is highly harmful to humans.

You might be interested in
67.029g to three significant figures
alexdok [17]
67.0 Should be th3 answer
5 0
3 years ago
Read 2 more answers
What describes the change in oxidation states of the following reaction
miskamm [114]
Cu  ions  reduced to  cu  and Al  oxidized to  Al  ions  is  the  answer.  copper   ions is right hand  side  of  the  E.M.F  cell  where  reduction  take  place  and is  reduced  to  copper  metal. Al   metal is  at left hand  side  of  the  E.m.f  cell where oxidation  take  place and  is  oxidized  to  Al  ions
7 0
3 years ago
Which of the following shows the correct path of blood through the heart and lungs?
jeyben [28]

Answer:

B

Explanation:

Always remember blood first flows from atria (remember A comes before V) to ventricles and the right side always carries deoxgenated blood to the lungs which then arrives through the left side when oxygenated

5 0
2 years ago
Read 2 more answers
Don't know how to solve
faltersainse [42]
Happy Valentines Day! <3
8 0
3 years ago
What binary compound would be formed from barium ions and fluoride ions?
LenaWriter [7]
Barium fluoride (BaF2) - Also known as Barium(II) fluoride - because it's a combination of two different kinds of ions (binary = two).
4 0
3 years ago
Read 2 more answers
Other questions:
  • Which molecule could have an expanded octet? hno2 h2co3 h3po4?
    11·1 answer
  • Which two values will a spontaneous reaction have?
    15·2 answers
  • Potassium (K) combines with magnesium bromide (MgBr2) to form potassium bromide (KBr) and magnesium (Mg) during a chemical react
    15·1 answer
  • Why is it important to use fine adjustment when focusing with the high power on a microscope?
    14·1 answer
  • Based on the oxidation states of the atoms in this reaction, answer the questions. 4Fe(0) + 3O2(0) → 2Fe2(3+)O3(2-) How many ele
    10·1 answer
  • A new compound was recently discovered and found to have an atomic weight of 342.38 amu. This element has two isotopes, the ligh
    13·1 answer
  • K2SO4(aq) + Ba(NO3)2(aq) → 2KNO3(aq) + BaSO4(s)
    5·2 answers
  • What independent variables can be tested in this lab setup? (List at least 5)
    13·1 answer
  • Why could prouts idea be considered a creative thought?​
    13·1 answer
  • 2 upper N upper O subscript 2 (g) right arrow 2 upper N upper o (g) plus upper O subscript 2 (g). Second: 2 upper N upper O (g)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!