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Yuki888 [10]
3 years ago
6

Explain The Law of Conservation of Mass​

Chemistry
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Hope it's helpful to you

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Write the complete balanced equation for Manganese & sulfuric acid --> Manganese (II) sulfate & water & sulfur di
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Answer:

I kinda forgot. I'm sorry if I didn't answer your question.

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3 years ago
1. The H atom and the Be +3 ion each have one electron. Does the Bohr model predict their spectra accurately? Would you expect t
lesantik [10]

Answer:

yes the Bohr model predicts their spectra accurately

Explanation:

The Bohr model based on one electron system

The atom H  has a single atom and the ion Be+3 has a single atom as well and this proves that the Bohr model predicts their spectra accurately .

also apply the equation model to further explain

E = \frac{-(z^2) (2.18 * 10^{-18}j) }{n^2}

z = atomic number

for H the value of z = 1

for Be+3 the value of z = 4

when this values are substituted into the equation above

E =  \frac{-(1) (2.18 * 10^{-18}j) }{n^2} ,   E = \frac{-(4) (2.18 * 10^{-18}j) }{n^2}

this results show that the energy  level of Be+3 is higher than the energy level of H by a factor of 16 , and this shows that their line patterns are similar

6 0
3 years ago
How many grams of cl are in 445 g of cacl2?
RideAnS [48]
<span>284 g First, lookup the atomic weights of all the elements involved. Atomic weight of Calcium = 40.078 Atomic weight of Chlorine = 35.453 Now calculate the molar mass of CaCl2 40.078 + 2 * 35.453 = 110.984 Using that molar mass, calculate how many moles of CaCl2 you have. 445 g / 110.984 g/mol = 4.009586967 mol Since each molecule of CaCl2 has 2 chlorine atoms, multiply the number of moles of CaCl2 by 2 to get the number of moles of Chlorine atoms. 4.009586967 * 2 = 8.019173935 And finally, multiply by the atomic weight of chlorine. 8.019173935 * 35.453 = 284.3037735 Since you have have 3 significant figures in your data, round the result to 3 significant figures, giving 284 grams.</span>
7 0
4 years ago
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