The purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
<h3>What is the importance of movement of the scapula during arm elevation?</h3>
The scapula is an important bone which is found in the shoulder and back region of the body.
The scapula enables and increases the range of motion of the arm with its motions.
During arm elevation, the scapula undergoes an upward rotational motion.
Therefore, the purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
Learn more about scapula motion at: brainly.com/question/5133017
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Answer:
Frequency is the number of wavelengths, which is measured in hertz.
Explanation:
I have my ways ;)
complete question:
A child bounces a 60 g superball on the sidewalk. The velocity change of the superball is from 22 m/s downward to 15 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk
Answer:
F = 1776 N
Explanation:
mass of ball = 60 g = 0.06 kg
velocity of downward direction = 22 m/s = v1
velocity of upward direction = 15 m/s = v2
Δt = 1/800 = 0.00125 s
Linear momentum of a particle with mass and velocity is the product of the mass and it velocity.
p = mv
When a particle move freely and interact with another system within a period of time and again move freely like in this scenario it has a definite change in momentum. This change is defined as Impulse .
I = pf − pi = ∆p
F = ∆p/∆t = I/∆t
let the upward velocity be the positive
Δp = mv2 - m(-v1)
Δp = mv2 - m(-v1)
Δp = m (v2 + v1)
Δp = 0.06( 15 + 22)
Δp = 0.06(37)
Δp = 2.22 kg m/s
∆t = 0.00125
F = ∆p/∆t
F = 2.22/0.00125
F = 1776 N
So power is considered as the rate of doing work. Base on the problem given, my analysis is that the machine who finish the work faster is machine C. Therefore, in order to finish the same amount of work in a short period of time you are going to expend the most power. My answer is Machine C.
