Question

I still walk four blocks north three blocks east for black stuff and then two blocks west where is the students distance and what is the students displacement

Answer 1

1) Distance: 9 blocks

2) Displacement: 4.12 blocks at $76^{\circ}$ north of east

Explanation:

1)

Distance is a scalar quantity that represents the total length of the path covered by a body during its motion, regardless of its direction. It can be calculated by simply adding the length of each part of the path.

In this problem, the motion of the person is:

4 blocks north

3 blocks east

2 blocks west

Therefore, the distance covered is just the sum of the length of each path:

distance = 4 + 3 + 2 = 9 blocks

2)

Displacement is a vector quantity connecting the initial position to the final position of the motion of a body. Since it is a vector, it has both a magnitude and a direction.

The magnitude can be computed by calculating the distance in a straight line between the initial and final position of motion.

In this problem, we have:

- The final position along the north-south direction is 4 blocks north

- The final position along the east-west direction is

(3 east) + (2 west) = 1 block east

Therefore, the magnitude of the displacement is given by Pythagorean's theorem:

$displacement = \sqrt{4^2 + 1^2}=4.12$ blocks

and the direction is given by

$\theta=tan^{-1}(\frac{4}{1})=76^{\circ}$ north of east.

Learn more about distance and displacement:

brainly.com/question/3969582

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