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Leokris [45]
3 years ago
10

A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string

, away from the ground, with the string at an angle of 69.4 degrees with the vertical. It is observed to have a speed of 8.00 m/s when it passes its lowest point. What was the speed of the stone (in meters/second) at the moment of release?
Physics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

v_{max}=8.2226m/s

Explanation:

The problem is solved using the law of conservation of energy,

So

mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}

v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}

v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}

v_{max}=8.2226m/s

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Answer:

\rho=1.8\times 10^{-8}\Omega.m

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Given:

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length of the wire, l=12\ m

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Now the net resistance of the wire:

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R=\frac{V}{I}

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R=1\ \Omega

We have the relation between the resistivity and the resistance as:

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a = cross sectional area of the wire

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1=\rho\times \frac{12}{1.8\times 10^{-3}\times 1.2\times 10^{-4}}

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3 years ago
If you move two objects father Paul how does the force of gravity between the two objects change
Yanka [14]
The force of gravity gets stronger.

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If the ankylosaurs starts running and accelerates at 1.3m/s^2 for 3 seconds how far does he make it before the velociraptor catc
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ipn [44]

Answer:

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Explanation:

Given:

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Answer:

Explanation:

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3 years ago
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