The loudness of the sound at the rock concert, where the intensity of the sound is1 x 10⁻¹ Wm⁻² is 110 dB.
Here we are dealing with loudness which is the perception of the Intensity of the sound.
The formula to refer to in order to find the value of the loudness of a sound is ,
db= 10log(I/I₀)
As we are provided with the current intensity which is 1 x 10⁻¹ Wm⁻². and the initial intensity which is 1 x 10⁻¹² Wm⁻².
So, by substituting the required values in the formula we get
db= 10 * log( 1 x 10⁻¹ /1 x 10⁻¹²)
= 10 * 11 log(10)
= 110
So, the result is 110 dB.
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We have that the spring constant is mathematically given as

Generally, the equation for angular velocity is mathematically given by

Where
k=spring constant
And

Therefore

Hence giving spring constant k

Generally
Mass of earth 
Period for on complete resolution of Earth around the Sun


Therefore


In conclusion
The effective spring constant of this simple harmonic motion is

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Answer:
-0.481 m/s^2
Explanation:
The force equation of this problem is given as:
F - W = ma
where F = upward force holding the clarinet bag
W = downward force (weight of the clarinet)
The mass of the clarinet bag is 3.010 kg, therefore, its weight is:
W = mg
W = 3.010 * 9.8 = 29.498
F = 28.05 N
Therefore:
28.05 - 29.498 = 3.010 * a
-1.448 = 3.010a
=> a = -1.448 / 3.010
a = -0.481 m/s^2
The acceleration of the bag is downward.
Answer:C: The gravity on the moon is less than the gravity on Earth.
Explanation:
Haven't taken physics but I would assume if her friend is standing in front of her that you would add up the speeds and get 30 km/hr.