The horizontal component of the magnetic field is 12.6 μT.
The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.
The horizontal component of the Earth's magnetic field is perpendicular to the axis of a circular coil with five turns and a diameter of D = 30.0 cm that is vertically orientated.
A coil current of I = 0.600 A causes a horizontal compass to deflect 45.0° from magnetic north when it is positioned in the coil's center.
Let B be the magnetic field and R be the radius of the circular coil.
Then the horizontal component of the Earth's magnetic field is given as:
B(h) = B(coil) = μ₀ NI / 2R
B(h) = (4π × 10⁻⁷ ) (5)(0.6) / 0.3
B(h) = 12.6 μT
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I believe I seen on google if you go to Mather
Wavelength*frequency=velocity
(331m/s)/(.6m)
Frequency = 551.666 1/s
The answer must be a mass x velocity
Answer:
1500m/s
Explanation:
d=180000
t=120
units have to be converted into SI Units
Average Speed = (Total distance)/(Total Time)
Average Speed= (180000)/(120)
