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igor_vitrenko [27]
3 years ago
13

Your boat capsizes but remains floating upside down. what should you do?

Physics
2 answers:
agasfer [191]3 years ago
8 0

On the chance that you capsize or swamp your boat, or if you have  fallen over the edge and can't get back in, stay with the boat if possible.

Further Explanation:

Try to shake a flag:

Your overwhelmed vessel is simpler to see and will flag that you are in a difficult situation. Additionally signal for assistance utilizing different gadgets accessible (visual trouble signals, whistle, reflect).  

Wear a PFD:

In the event that you committed the error of not wearing a PFD, discover one and put it on. In the event that you can't put it on, clutch it. Have your travelers do likewise.  

Head check:

Take a head check. Reach, toss, push, or go, if necessary.  

On the top of boat

On the off chance that your boat stays above water, attempt to reboard or climb onto it so as to get however much of your body out of the virus water as could be expected. Stepping water will make you lose body heat quicker, so attempt to utilize the pontoon for help.

Answer Details:

Subject: Physics

Level: High School.

Key Words:

Try to shake a flag:

Wear a PFD:

Head check:

On the top of boat

For further Evaluation :

brainly.com/question/10872128

brainly.com/question/4379740

Ludmilka [50]3 years ago
5 0

<span>You should stay on the top of the boat, this will help rescuers find you because a boat is easier to find than a small body in a large ocean. Never swim away from the boat you could catch a cold and/ or get hypothermia or drift far away from where you were last seen. This will make the search much harder.</span>

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ohaa [14]

Answer:

b) 472HZ, 408HZ

Explanation:

To find the frequencies perceived when the bus approaches and the train departs, you use the Doppler's effect formula for both cases:

f_o=f\frac{v_s+v_o}{v_s-v}\\\\f_o=f'\frac{v_s-v_o}{v_s+v}\\\\

fo: frequency of the source = 440Hz

vs: speed of sound = 343m/s

vo: speed of the observer = 0m/s (at rest)

v: sped of the train

f: frequency perceived when the train leaves us.

f': frequency when the train is getTing closer.

Thus, by doing f and f' the subjects of the formulas and replacing the values of v, vo, vs and fo you obtain:

f=f_o\frac{v_s-v}{v_s+v_o}=(440Hz)\frac{340m/s-25m/s}{340m/s}=408Hz\\\\f'=f_o\frac{v_s+v}{v_s-v_o}=(440Hz)\frac{340m/s+25m/s}{340m/s}=472Hz

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b) 472HZ, 408HZ

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We have that the letter A in the diagram below given as

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Option A

<h3>Amplitude</h3>

Question Parameters:

Amplitude

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