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igor_vitrenko [27]
3 years ago
13

Your boat capsizes but remains floating upside down. what should you do?

Physics
2 answers:
agasfer [191]3 years ago
8 0

On the chance that you capsize or swamp your boat, or if you have  fallen over the edge and can't get back in, stay with the boat if possible.

Further Explanation:

Try to shake a flag:

Your overwhelmed vessel is simpler to see and will flag that you are in a difficult situation. Additionally signal for assistance utilizing different gadgets accessible (visual trouble signals, whistle, reflect).  

Wear a PFD:

In the event that you committed the error of not wearing a PFD, discover one and put it on. In the event that you can't put it on, clutch it. Have your travelers do likewise.  

Head check:

Take a head check. Reach, toss, push, or go, if necessary.  

On the top of boat

On the off chance that your boat stays above water, attempt to reboard or climb onto it so as to get however much of your body out of the virus water as could be expected. Stepping water will make you lose body heat quicker, so attempt to utilize the pontoon for help.

Answer Details:

Subject: Physics

Level: High School.

Key Words:

Try to shake a flag:

Wear a PFD:

Head check:

On the top of boat

For further Evaluation :

brainly.com/question/10872128

brainly.com/question/4379740

Ludmilka [50]3 years ago
5 0

<span>You should stay on the top of the boat, this will help rescuers find you because a boat is easier to find than a small body in a large ocean. Never swim away from the boat you could catch a cold and/ or get hypothermia or drift far away from where you were last seen. This will make the search much harder.</span>

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Sharon is driving on a straight road. She is driving north, and her speed is
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b

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A crude approximation for the x component of velocity in an incompressible laminar boundary layer is a linear variation from u =
slega [8]

Answer:

2.5 * 10^-3

Explanation:

<u>solution:</u>

The simplest solution is obtained if we assume that this is a two-dimensional steady flow, since in that case there are no dependencies upon the z coordinate or time t. Also, we will assume that there are no additional arbitrary purely x dependent functions f (x) in the velocity component v. The continuity equation for a two-dimensional in compressible flow states:

<em>δu/δx+δv/δy=0</em>

so that:  

<em>δv/δy= -δu/δx</em>

Now, since u = Uy/δ, where δ = cx^1/2, we have that:

<em>u=U*y/cx^1/2</em>

and we obtain:  

<em>δv/δy=U*y/2cx^3/2</em>

The last equation can be integrated to obtain (while also using the condition of simplest solution - no z or t dependence, and no additional arbitrary functions of x):  

v=∫δv/δy(dy)=U*y/4cx^1/2

 =y/x*(U*y/4cx^1/2)

 =u*y/4x

which is exactly what we needed to demonstrate.  

Also, using u = U*y/δ in the last equation we can obtain:  

v/U=u*y/4*U*x

     =y^2/4*δ*x

which obviously attains its maximum value for the which is y = δ (boundary-layer edge). So, finally:

(v/U)_max=δ^2/4δx

                =δ/4x

                =2.5 * 10^-3

7 0
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Explanation:

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       W sin θ = m a

 

       mg sin θ = m a

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let's calculate

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8 0
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2 years ago
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