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2 years ago

Your boat capsizes but remains floating upside down. what should you do?

2 answers:

8 0

On the chance that you capsize or swamp your boat, or if you have fallen over the edge and can't get back in, stay with the boat if possible.

Further Explanation:

Try to shake a flag:

Your overwhelmed vessel is simpler to see and will flag that you are in a difficult situation. Additionally signal for assistance utilizing different gadgets accessible (visual trouble signals, whistle, reflect).

Wear a PFD:

In the event that you committed the error of not wearing a PFD, discover one and put it on. In the event that you can't put it on, clutch it. Have your travelers do likewise.

Head check:

Take a head check. Reach, toss, push, or go, if necessary.

On the top of boat

On the off chance that your boat stays above water, attempt to reboard or climb onto it so as to get however much of your body out of the virus water as could be expected. Stepping water will make you lose body heat quicker, so attempt to utilize the pontoon for help.

Answer Details:

Subject: Physics

Level: High School.

Key Words:

Try to shake a flag:

Wear a PFD:

Head check:

On the top of boat

For further Evaluation :

brainly.com/question/10872128

brainly.com/question/4379740

Ludmilka [50]2 years ago

5 0

<span>You should stay on the top of the boat, this will help rescuers find you because a boat is easier to find than a small body in a large ocean. Never swim away from the boat you could catch a cold and/ or get hypothermia or drift far away from where you were last seen. This will make the search much harder.</span>

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Consider an e. coli to be a cylinder with a diameter of 1 micrometer (um) and with a length of 2 micrometer (um).

julia-pushkina [17]

Answer:

$A=6.28\ \mu m^2$

Part 1

$V=1.57 \ \mu m^3$

Part 2

$A=6.28\ \mu m^2$

Explanation:

Given that

Diameter,d=1 μm

Length ,l=2 μm

As we know that volume of cylinder given as

$V=\pi r^2l$

$V=\pi \times 0.5^2\times 2 \ \mu m^3$

$V=1.57 \ \mu m^3$

Surface area,A

A=π d l

$A=\pi \times 1 \times 2\ \mu m^2$

$A=6.28\ \mu m^2$

Part 1

$V=1.57 \ \mu m^3$

Part 2

$A=6.28\ \mu m^2$

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3 years ago

Apakah soalan tingkatan 4 bm negeri selangor

noname [10]

What does this mean? What do you need help with?

8 0

3 years ago

While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 6.63 m/s. The stone s

gogolik [260]

Answer:

Speed=28.1m/s(to 3s.f.) , Time=2.19s(to 3s.f.)

Explanation:

Time=Distance/Speed

=14.5/6.63

=2.19s(to 3s.f.)

Acceleration=Final Velocity(v)-Initial Velocity(u)/Time

9.81=v-6.63/2.19

v-6.63=21.5

v=28.1m/s

3 0

2 years ago

How can the motion of a charged particle be used to distinguish between a magnetic field and an electric field in a certain regi

Helen [10]

Answer:

The charged particle follows a spiral path in a magnetic field.

Explanation:

A charge immersed in a region with an electric field experiences a force that acts along the same direction of the electric field. In particular:

- The force has the same direction as the electric field if the charge is positive

- The force has the opposite direction as the electric field if the charge is negative

Therefore, a charge moving in an electric field is accelerated along the direction of the electric field.

On the other hand, a charge in motion in a region with a magnetic field experiences a force that acts perpendicular to the direction of the field. This means that a charge in motion in a magnetic field will acquire a circular motion in the plane perpendicular to the direction of the magnetic field.

As a result, if the particle has also a original motion outside this plane, its final motion will consist of:

- A uniform motion along that direction, +

- A circular motion along the plane perpendicular to the field

So, the resultant motion of the particle will be a spiral path. So the correct answer is

The charged particle follows a spiral path in a magnetic field.

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2 years ago

Which of the following objects requires the MOST power to lift?

Nesterboy [21]

Answer:

Explanation:

Work = F * d

Power = work/time or f *d / t

' A ' gives the highest amount of power

5 0

1 year ago