Answer:
The frequency of the simple harmonic motion of a 67.6 kg diver on the board = 2.48 Hz
Explanation:
The frequency in simple harmonic motion is related to spring constant and mass causing the motion through the relation
f = (1/2π) √(k/m)
When mass = 10 kg, f = 6.90 Hz,
6.9 = (1/2π) √(k/10)
(√(k/10) = 6.9×2π = 43.354
k/10 = 43.354² = 1879.57
K = 18795.7 N/m
When a diver of mass 67 kg climbs the diving board, the total mass on the diving board now becomes (10+67.6) = 77.6 kg
Spring constant of the diving board doesn't change,
So, the frequency is then given by
f = (1/2π) √(18795.7/77.6)
f = 2.48 Hz
Answer:
Explanation:
K.E is 1/2 mv^2
Therefore KE is 300000×10000×1/2
=1500000000J
= 1500000KJ
Potential energy is mgh
Therefore PE is 300000×9.8×2000
=5,880,000,000J
=5880000KJ
I would say its c
given a fixed volume, when volume decreases while mass remains constant
density increases ie temperature increases also
Answer:
B. 14.4 N
Rotational speed (Angular Velocity) = 2
The Radius of the circle = 1.2 m
Velocity = Angular velocity × radius = 2×1.2 = 2.4 m/s
Centripetal force= mv²/r = 3 × 2.4×2.4/1.2 = 3 × 2.4 × 2
= 14.4 N
