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uysha [10]
2 years ago
5

How to calculate this operation? m=10kg and L=2500J/kg? What is the Energy?

Physics
1 answer:
Ber [7]2 years ago
7 0

Answer:

25000J

Explanation:

Formula : Q = m×c×Δt

Q=Heat energy

m= mass

c=specific heat capacity

ΔT = change in temperature.

Q=M x C for this question.

Specific heat capacity = 2500 J/Kg

Mass = 10kg

2500 x 10 = 25000 J

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If a car is traveling at a speed of 45 miles per hour, how far<br>can it travel in 40 minutes?​
dusya [7]

Answer:

30 miles

Explanation:

<u>Step 1:</u>

Divide -> 45/60= .75 miles/minute

<u>Step 2:</u>

Multiply -> .75 x 40= 30

3 0
3 years ago
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A 6.5 x 104 W engine exerts a constant force on of 5.5 x 103 N on a car, the resulting velocity is?
jek_recluse [69]

Answer:

12m/s

Explanation:

Given parameters:

Power = 6.5 x 10⁴W

Force  = 5.5 x 10³N

Unknown:

The resulting velocity  = ?

Solution:

 The velocity of a body is related to force and power using the expression below;

            Power  = Force x velocity

Insert the parameters and solve for velocity

         6.5 x 10⁴  = 5.5 x 10³ x velocity

          velocity  = \frac{6.5 x 10^{4} }{5.5 x 10^{3} }   = 12m/s

4 0
2 years ago
If you see a swimmer in distress you should:
mestny [16]
Check-call-Care if you are training to be a life guard.
3 0
3 years ago
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A force of 1 newton will cause a mass of 1 kg to have an acceleration of 1 m/s^2. If a force of 5 newtons is applied to a mass o
nignag [31]

For any force and any mass, the acceleration is always

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If a force of 5 newtons is applied to a mass of 5 kg, the acceleration will be

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7 0
3 years ago
If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.503 X 104 T) at a distance of 15
dem82 [27]

Answer:

37.725 A

Explanation:

B = magnitude of the magnetic field produced by the electric wire = 0.503 x 10⁻⁴ T

r = distance from the wire where the magnetic field is noted = 15 cm = 0.15 m

i = magnitude of current flowing through the wire = ?

Magnetic field by a long wire is given as

B = \frac{\mu _{o}}{4\pi }\frac{2i}{r}

Inserting the values

0.503\times 10^{-4} = (10^{-7})\frac{2i}{0.15}

i = 37.725 A

6 0
2 years ago
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