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andreev551 [17]
3 years ago
11

In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t

ime interval sunshine coming through the windows delivered 2000 J of energy into the house. The temperature of the house didn't change. What was ?Ethermal of the house, and what was |Q|, the magnitude of the energy transfer between the house and the outside air?
?Ethermal = J

|Q| = J
Physics
1 answer:
Bumek [7]3 years ago
5 0

Explanation:

Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.

Hence, \Delta E = 0. And, as \Delta E = 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.

Therefore,

                   Q = -(19000 J + 2000 J)

                       = -21000 J

or,    |Q| = 21000 J

Thus, we can conclude that the magnitude of the energy transfer between the house and the outside air is 21000 J.

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3 0
3 years ago
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
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Answer:\tau=1.03\times 10^{-4}\ N-m

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\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

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