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s2008m [1.1K]
3 years ago
10

Conversion fraction 1$=4q, how many are in 20$

Physics
2 answers:
Tom [10]3 years ago
8 0

Answer:

\boxed{\sf 20 \$ = 80q}

Given:

1$ = 4q

To Find:

How many quarters are in 20$

Explanation:

To find out how many quarters are in 20$ we need to multiple 4 × 20.

\sf 1\$  = 4q

\sf  20\$  = 4 \times 20q

\sf = 80q

Over [174]3 years ago
7 0

Answer:

\boxed{\sf 20 \$ = 80q}

Given:

1$ = 4q

To Find:

How many quarters are in 20$

Explanation:

To find out how many quarters are in 20$ we need to multiple 4 × 20.

\sf 1\$  = 4q

\sf  20\$  = 4 \times 20q

\sf = 80q

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Materials in which electric charges move freely such as copper and aluminum are called
yuradex [85]

Answer:

Conductors allow electric charges to move freely

8 0
3 years ago
Describe what happens to the electric field lines when two objects with unlike charges are brought near each other.
harina [27]
Hello.

The answer is:

It creates a spark.

Then thespark can sometimes start a fire or other serious problems.

Have a nice day
4 0
3 years ago
Read 2 more answers
A 1000kg car is rolling slowly across a level surface at 1 m/s heading twoards a group o fsmall innocent children. The doors are
Degger [83]

Answer:

The force required to push to stop the car is 288.67 N

Explanation:

Given that

Mass of the car, m = 1000 kg

Initial speed of the car, u = 1 m/s

The car and push on the hood at an angle of 30° below horizontal, \theta=30^{\circ}

Distance, d = 2 m

Let F is the force must you push to stop the car.

According work energy theorem theorem, the work done is equal to the change in kinetic energy as :

W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)

v = 0

Fd\ cos\theta=\dfrac{1}{2}m(u^2)      F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N

The force required to push to stop the car is 288.67 N

3 0
3 years ago
Please help
Allisa [31]

<u>We are given:</u>

Mass of the rocket = 10 kg

Weight of the Rocket = 100 N

Upward thrust applied by the rocket = 400 N

<u>Net upward force on the rocket:</u>

We are given that gravity pulls the rocket with a force of 100 N

Also, the rocket applied a force of 400N against gravity

Net upward force = Upward thrust - Force applied by gravity

Net upward force = 400 - 100

Net upward force = 300 N

<u>Upward Acceleration of the Rocket:</u>

From newton's second law:

F = ma

<em>replacing the variables</em>

300 = 10 * a

a = 30 m/s²

5 0
3 years ago
Help asap!
patriot [66]

Answer:

220 V

Explanation:

r_{1} = 20 ohm\\r_{2} = 30ohm\\r_{3} = 60ohm

As the resistors are connected in series,

R_{eq} = r_{1} +r_{2} +r_{3}

= 20 + 30 + 60

= 110 ohms

V = IR

= 2 * 110

= 220 V

Hope it helps

7 0
3 years ago
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