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3 years ago

with respect to composition, how is the compound made from hydrogen and oxygen different from mixtures of these two elements?

1 answer:

8 0

Each substance in the mixture keeps its own properties and can be easily separated from the mixture. In a mixture of hydrogen and oxygen, molecules of both the gases will exist independently.
The compound on the other hand has properties different from the elements it contains. In water as a compound of hydrogen and oxygen what you will have is molecules of H20.

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What molecule is responsible for chemical digestion.

padilas [110]

Answer:

Amylase.

Explanation:

The process of digestion begin to start in mouth when food mix with saliva. An enzyme is released which is called Amylase help in digestion of carbohydrates.

8 0

3 years ago

When a scientist uses reasoning to explain or interpret the things they observe

Kipish [7]

Answer:

Inferring is when a scientist uses reasoning to explain or interpret the things they observe

7 0

3 years ago

A neutralization reaction is a reaction between choose. That results in the formation of choose. And choose.

andrey2020 [161]

Neutralization reaction is the reaction that occur between acid and base.

<h3>What is Neutralization reaction?</h3>

Neutralization reaction is the reaction that take place between acid and base to produce salt and water. For examples HCl react with NaOH to produce NaCl and H2O

Therefore, Neutralization reaction is the reaction between acid and base.

The question is not complete but the option are gotten from another website.

Here are the options.

an acid and a base
a fuel and oxygen
an acid and a metal
a salt and a base

Learn more about neutralization from the link below.

brainly.com/question/4090568

8 0

2 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

Could someone help me with this?

Varvara68 [4.7K]

Solving part-1 only

KMnO_4

Transition metal is Manganese (Mn)

Actually it's the oxidation number of Mn

Let's find how?

$\\ \tt\Rrightarrow x+1+4(-2)=0$

$\\ \tt\Rrightarrow x+1-8=0$

$\\ \tt\Rrightarrow x-7=0$

$\\ \tt\Rrightarrow x=+7$

x is the oxidation number

Purple as per the color of potassium permanganate

$\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}$

7 0

2 years ago