Answer:
where a cold air mass is replacing a warmer air mass. ... The air behind a cold front is noticeably colder and drier than the air ahead of it. When a cold front passes through, temperatures can drop more than 15 degrees within the first hour.
Explanation:
The effects from a cold front can last from hours to days. The air behind the front is cooler than the air it is replacing and the warm air is forced to rise, so it cools. As the cooler air cannot hold as much moisture as warm air, clouds form and rain occurs.
36 micrograms is the answer
Answer:
Odds to be given for an event that either Romance or Downhill wins is 11:4
Explanation:
Given an odd, r = a : b. The probability of the odd, r can be determined by;
Pr(r) =
÷ (
So that;
Odd that Romance will win = 2:3
Pr(R) =
÷ (
=
÷ ![\frac{5}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7D)
= ![\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D)
Odd that Downhill will win = 1:2
Pr(D) =
÷ (
=
÷ ![\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D)
= ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
The probability that either Romance or Downhill will win is;
Pr(R) + Pr(D) =
+ ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
= ![\frac{11}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B15%7D)
The probability that neither Romance nor Downhill will win is;
Pr(neither R nor D) = (1 -
)
= ![\frac{4}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B15%7D)
The odds to be given for an event that either Romance or Downhill wins can be determined by;
= Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)
=
÷ ![\frac{4}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B15%7D)
= ![\frac{11}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B4%7D)
Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4
Increase, because you need heat to melt a solid to a liquid, so the temperature will have to get greater.