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alukav5142 [94]
3 years ago
6

What is the average atomic mass?

Chemistry
1 answer:
zysi [14]3 years ago
5 0

Answer: The answer to this average atomic mass is 941.337184

Explanation I just added them up to find my solution.

You might be interested in
It is expected that a chemical reaction will occur when copper metal is combined with aqueous zinc sulfate. Explain why there wi
REY [17]

Answer:

E_{cell}= +ve, reaction is spontaneous

E_{cell}= -ve, reaction is non spontaneous

E_{cell}= 0, reaction is in equilibrium

Case 1: when copper metal is combined with aqueous zinc sulfate.

Cu+ZnSO_4\rightarrow Zn+CuSO_4

Here copper is undergoing oxidation ad thus acts as anode and zinc is undergoing reduction , thus acts as cathode.

E^o_{cell} = standard electrode potential =E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Cu^{2+}/Cu]}= +0.34V

E^0_{[Zn^{2+}/Zn]}= -0.76V

E^0=E^0_{[Zn^{2+}/Zn]}- E^0_{[Cu^{2+}/Cu]}

E^0=-0.76-(+0.34)=-1.10V

Thus as E_{cell} is negative , the reaction is non spontaneous.

Case 2: when zinc metal and aqueous copper sulfate solution are combined.

Zn+CuSO_4\rightarrow Cu+ZnSO_4

Here zinc is undergoing oxidation ad thus acts as anode and copper is undergoing reduction , thus acts as cathode.

E^o_{cell} = standard electrode potential =E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Cu^{2+}/Cu]}= +0.34V

E^0_{[Zn^{2+}/Zn]}= -0.76V

E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Zn^{2+}/Zn]}

E^0=+0.34-(-0.76)=+1.10V

Thus as E_{cell} is positive , the reaction is spontaneous.

3 0
4 years ago
If you have 600g of nitroglycerin, how many moles do you have?<br><br> help please
aleksandr82 [10.1K]

Answer:

600

Explanation:

there's 1 mole in every nitroglycerin

I think

5 0
3 years ago
How far would Sara get if she ran for 87 minutes at a speed of .125 miles per minute?
Elza [17]

Answer:

10.875 miles

So 87 minutes

.125 miles per minute

So just multiply int his case

87*.125

You’d get 10.875

7 0
3 years ago
What is the mass of a cube measuring 3cm on each side that had a density of 8.1g/cm3?
Hunter-Best [27]

Answer:

48.6 g

Explanation:

Given data:

Length of one side = 3 cm

Density of cube = 8.1 g/cm³

Mass of cube = ?

Solution:

First of all we will calculate the volume of cube.

V = length × height × width

V = 3 cm × 3cm× 3cm

V = 27cm³

Now we will determine the mass by using density formula.

d = m/v

d = density

m = mass

v = volume

8.1 g/cm³ = m/ 27 cm³

m = 8.1 g/cm³ ×27 cm³

m = 48.6 g

6 0
3 years ago
Instructions: After doing research to answer the objective question below, write a CER. Be sure to use credible sources (no wiki
Anon25 [30]
No Eaton segura lol lo sieto
3 0
4 years ago
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