Answer:
In particle physics, a lepton is an elementary particle of half-integer spin (spin 1⁄2) that does not undergo strong interactions.[1] Two main classes of leptons exist: charged leptons (also known as the electron-like leptons or muons), and neutral leptons (better known as neutrinos). Charged leptons can combine with other particles to form various composite particles such as atoms and positronium, while neutrinos rarely interact with anything, and are consequently rarely observed. The best known of all leptons is the electron.
1). the product of the two masses being gravitationally attracted to each other
2). the distance between their centers of mass
And that's IT. The gravitational force between them depends on
only those two things, nothing else.
Answer:
a. by moving the book without acceleration and keeping the height of the book constant
Explanation:
FOR CONSTANT KINETIC ENERGY:
The kinetic energy of a body depends upon its speed according to its formula:
ΔK.E = (1/2)mΔv²
So, for Δv = 0 m/s
ΔK.E = 0 J
So, for keeping kinetic energy constant, the books must be moved at constant speed without acceleration.
FOR CONSTANT POTENTIAL ENERGY:
The potential energy of a body depends upon its height according to its formula:
ΔP.E = mgΔh
So, for Δh = 0 m/s
ΔP.E = 0 J
So, for keeping potential energy constant, the books must be moved at constant height.
So, the correct option is:
<u>a. by moving the book without acceleration and keeping the height of the book constant</u>
Answer:
The magnitude of the electric field between the plates is half its initial value.
Explanation:
We know the electric field E = V/d where V = voltage applied and d = separation between plates.
Since V is constant and V = Ed,
So, E₁d₁ = E₂d₂ where E₁ = initial electric field at separation d₁, d₁ = initial separation of plates, E₂ = final electric field at separation d₂ and d₂ = final separation of plates.
So, E₂ = E₁d₁/d₂
Now, the distance between the plates is twice their original separation. Thus, d₂ = 2d₁
So, E₂ = E₁d₁/2d₁ = E₁/2
So, E₂ = E₁/2
Thus, the magnitude of the electric field between the plates is half its initial value.
In a displacement/time graph, the slope of the line is equal to the velocity
