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k0ka [10]
3 years ago
5

HEY CAN ANYONE PLS ANSWER DIS RQ!!!!

Physics
1 answer:
Bezzdna [24]3 years ago
8 0

Answer:

Negative

Explanation:

If you have to move the decimal point to the right to get the original number, the exponent will be a positive number, if you have to move the decimal point to the left to get the original number, the exponent will be a negative number.

Hope this helped!

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A wave has a frequency of 6 Hz and a speed of 30 m/s. What is the wavelength of the wave?
Helen [10]

Answer:

D. 5m

Explanation:

fλ = c, where f is frequency, λ is wavelength and c is speed.

6λ=30

λ=30/6=5

5 0
3 years ago
A bowling ball has a mass of 50 kg and is traveling with a velocity of 18 m/s 4 points
IRISSAK [1]

momentum= mass × velocity

p= 50×18

momentum= 900 kg m/s

4 0
3 years ago
A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is 8.9 nC ( 8.9 10-9 C), how man
Alika [10]

Answer:

Number of electrons, n=5.56\times 10^{10}

Explanation:

Given that,

Charge on the fur, q=8.9\ nC=8.9\times 10^{-9}\ C

A piece of amber is charged by rubbing with a piece of fur. We need to find the electrons were added to the amber. It can be calculated using the quantization of charge as

q = n × e

Where

n is the number of electrons

e is the charge on electron

n=\dfrac{q}{e}

n=\dfrac{8.9\times 10^{-9}}{1.6\times 10^{-19}}

n=5.56\times 10^{10}\ electrons

So, n=5.56\times 10^{10}\ electrons number of electrons are added to the amber. Therefore, this is the required solution.

7 0
3 years ago
Answer ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀​
ikadub [295]

\sf \huge \purple{ Question : -  }

Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².

\sf \huge \color {gold}{ AnSwer :- }

Initial velocity, u = 36 km/h

\sf u = 36 \times  \dfrac{5}{18}  {ms}^{ - 1}  = 10 {ms}^{ - 1}

Time, t = 1min

  • t = 60s

Acceleration, a = 2m/s²

Apply 2nd equation of motion

\longrightarrow \sf s = ut +  \dfrac{1}{2} at ^{2}  \\  \\  \longrightarrow \sf s =(10)(60) +  \frac{1}{2} (2)(60) {}^{2}  \\  \\  \longrightarrow \sf s =600 + 3600   \\  \\  \longrightarrow \sf  \blue{ s =4200m}  \:  \: \large \blue \star

6 0
3 years ago
Is the largest planet, with an atmosphere of mostly hydrogen and helium, and the great red spot
rodikova [14]
Jupiter, or mars that is the answer and your sentence throu me off a bit lol
8 0
3 years ago
Read 2 more answers
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