A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock

is 4.50 m/s. What is the centripetal force acting on the rock

1 answer:

5 0

$F = m \frac{v^2}{r}$

$F= 0.58 \frac{4.5^2}{0.5} = 23.49 N$

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