Answer:
Explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you plz don't forget to thank me...
Answer:
T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N
Explanation:
a.)
Period: It is already given in the question "oscillator repeats its motion every 0.372 s".
So T=0.372 s
b)
frequency= f = 1/ T
f = 1/ 0.372
f=2.7 Hz
c).
Angular frequency= w= 2πf
w= 2*π*2.7
w=16.9 rad/s
d)
Spring Constant:
As w=
⇒w²= k/m
⇒k= m*w²
⇒k= 0.628 * 16.9² N/m
⇒k=179.2 N/m
e)
The mass will have maximum speed when it passes through the mean position.
At mean position
Maximum elastic potential energy = Maximum kinetic energy
1/2 k A² = 1/2 m v² ( A is amplitude of oscillation)
⇒ v=
⇒ v=
\
⇒ v= 8.78 m/s
f)
Maximum force will be exerted on the block when it is at maximum distance.
F= k* A ( A is amplitude of oscillation)
F= 179.2 * 0.27 N
F= 48.4 N
Answer:
(a): emf =
(b): Amplitude of alternating voltage = 20.942 Volts.
Explanation:
<u>Given:</u>
- Area of the coil = A.
- Number of turns of coil = N.
- Magnetic field = B
- Rotation frequency = f.
(a):
The magnetic flux through the coil is given by

where,
= area vector of the coil directed along the normal to the plane of the coil.
= angle between
and
.
Assuming, the direction of magnetic field is along the normal to the plane of the coil initially.
At any time t, the angle which magnetic field makes with the normal to the plane of the coil is 
Therefore, the magnetic flux linked with the coil at any time t is given by

According to Faraday's law of electromagnetic induction, the emf induced in the coil is given by

(b):
The amplitude of the alternating voltage is the maximum value of the emf and emf is maximum when 
Therefore, the amplitude of the alternating voltage is given by

We have,

Putting all these values,

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