I think the answer is (d) 697.08 j hope helped
a) U = 0 J
k = 0.383 J
E = 0.383 J
b) U = 0.0228 J
k = 0.155 J
E = 0.383 J
c) U = 0.1104 J
k = 0.272 J
E = 0.383 J
d) U = 0.248 J
k = 0.177 J
E = 0.383 J
<h3>Method for solving:</h3>
The equations for kinetic energy is:
k= 1/2*m*
The equation for elastic potential energy is:
U= 1/2*ks*
Where,
m= mass of the block
v= velocity
ks= spring constant
x= displacement of the spring
(a)when compression= 0 cm
U= 1/2*ks*
U= 1/2*552*
= 0 J
Kinetic energy:
k= 1/2*m*
k= 1/2*(1.05)*
k= 0.383 J
Mechanical energy:
E= k + U
E= 0.383+0
E= 0.383 J
- There will be no work done by friction or any other dissipative force, hence this energy will be conserved, or it will remain constant (like air resistance).
- This indicates that only spring potential energy will be created from the kinetic energy (there is no thermal energy due to friction, for example).
(b) spring potential = ?
U= 1/2* 457 N/m*
U= 0.0228 J
Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:
E= k + U
0.383= k + 0.0228
k= 0.383 - 0.228
k= 0.155
(c)spring constant when x= 0.02
U= 1/2*552*
U= 0.1104 J
Using the equation of mechanical energy:
E= k +U
0.383= k+ 0.1104
k= 0.383 - 0.1104
k= 0.272 J
(d) U= 1/2*552*
U= 0.2484 J
E= 0.383 J
k = E - U
k= 0.383- 0.206
k= 0.177
To learn more about spring potential energy visit:
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Answer:
17.11m
Explanation:
Weight of the block is ,
#Component of the weight acting normal to ramp is:
#Component of the weight acting parallel to the ramp and against block's motion :
Force of kinetic friction parallel to ramp and against block's motion:
We can now calculate deceleration up incline:
#The time,, of block's motion up incline is given as:
The block moves 17.11m up the incline.
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