Ask question

Ask question

All categories

2 years ago

8

Suppose the conducting wire (with resistance R) was replace with one of the same material but has its dimension doubled (the len

gth and the radius having twice their original value. What is the new resistance in comparison to the previous resistance?

1 answer:

sveticcg [70]2 years ago

6 0

Resistance of a wire is directly proportional to its length and inversely proportional to the square of its radius.
Thus, if the length is doubled, and the radius is halved:
R₂ = 2R₁/(1/2)²
R₂ = 8R₁
Therefore the resistance increases eight times.

You might be interested in

Key concepts <br><br> (Example | scientific method

nekit [7.7K]

Vocabulary should be, I think:
I. Hypothesis
II. Evidence, data
III. Experiment

What is your question exactly?

3 0

3 years ago

Read 2 more answers

Can someone explain to me what potential difference is? Simple answers are always better! P.s : Last time my electricity questio

Artyom0805 [142]

<span>the difference of electrical potential between two points. hope this helps</span>

3 0

3 years ago

It is important to use the correct drying tempture because it prevents shrinkage and will not damage the garment.

Nina [5.8K]

Answer:

fjowe

Explanation:

kbegtrf3g4ef j3kq4ef 3w4beysrf2w4er8f6ywgbaebf7v2wy4egdwa4i6e5

7 0

2 years ago

Read 2 more answers

A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a

svlad2 [7]

Answer:

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

the apple should be tossed after $\Delta t=0.0173\ s$

Explanation:

Given:

velocity of arrow in projectile, $v=30\ m.s^{-1}$

angle of projectile from the horizontal, $\theta=20^{\circ}$

distance of the point of tossing up of an apple, $d=30\ m$

<u>Now the horizontal component of velocity:</u>

$v_x=v\ cos\ \theta$

$v_x=30\times cos\ 20^{\circ}$

$v_x=28.191\ m.s^{-1}$

<u>The vertical component of the velocity:</u>

$v_y=v.sin\ \theta$

$v_y=30\times sin\ 20^{\circ}$

$v_y=10.261\ m.s^{-1}$

<u>Time taken by the projectile to travel the distance of 30 m:</u>

$t=\frac{d}{v_x}$

$t=\frac{30}{28.191}$

$t=1.0642\ s$

<u>Vertical position of the projectile at this time:</u>

$h=v_y.t-\frac{1}{2}g.t^2$

$h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2$

$h=5.3701\ m$

<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

$v'^2=u'^2-2g.h$

$0^2=u'^2-2\times 9.8\times 5.3701$

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

$v'=u'-g.t'$

$0=10.259-9.8\times t'$

$t'=1.0469\ s$

<u>We observe that </u> $t>t'$ <u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

$\Delta t=t-t'$

$\Delta t=1.0642-1.0469$

$\Delta t=0.0173\ s$

8 0

3 years ago

Three rocks with masses of 1 kg, 5 kg, and 10 kg fall from the same height.

Naily [24]

Answer:
The 10 kg rock has more inertia than the other two rocks.

Explanation

4 0

2 years ago

Read 2 more answers