If an element an atomic number of 32 and a mass of 72, how many neutrons does it have?

Electroencephalography (EEG), in which electrodes placed on the scalp pick up electrical signals underneath, and magnetoencephal

Alexxx [7]

Does electrical curents flows of charges across the membrane and the depolarization continues also due to charges that reject each other and the flow continues .so there appears a magnetic field as well

6 0

2 years ago

If you stood on mars and lifted a 15kg pack, you would be pulling with a force greater than...?

DIA [1.3K]

Answer:

See the answers below

Explanation:

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

$W=m*g$

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

$w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\$

Venus

$w_{venus}=15*8.8\\w_{venus}= 132 [N]$

Moon

$w_{moon}=15*1.6\\w_{moon}=24[N]$

Mars

$w_{mars}=15*3.7\\w_{mars}=55.5 [N]$

Jupiter

$w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N]$

Saturn

$w_{saturn}=15*9\\w_{saturn}=135[N]$

Uranus

$w_{uranus}=15*8.7\\w_{uranus}=130.5[N]$

Neptune

$w_{neptune}=15*11\\w_{neptune}=165[N]$

Pluto

$w_{pluto}=15*0.6\\w_{pluto}=9[N]$

7 0

1 year ago

Suppose a treadmill has an average acceleration of 4.7x10^-3 m/s. a)how much does its speed change after 5min? b)if the treadmil

Mars2501 [29]

Answer:

a)Change in the speed = 1.41 m/s

b)The final speed will be 3.11 m/s

Explanation:

Given that

Acceleration ,a= 4.7 x 10⁻³ m/s²

a)

We know that

v= u + a t

v=final speed ,u=initial speed

t= time ,a= acceleration

Change in the speed

v- u = a t

t= 5 min = 5 x 60 s = 300 s

v- u = 4.7 x 10⁻³ x 5 x 60 m/s

v-u = 1.41 m/s

Change in the speed = 1.41 m/s

b)

Given that

u= 1.7 m/s

v-u = 1.41 m/s

v= 1.7 + 1.41 m/s

v=3.11 m/s

The final speed will be 3.11 m/s

8 0

2 years ago

An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in

Anestetic [448]

Answer:

The value is $a = 4.0 \ m/s^2$

Explanation:

From the question we are told that

The velocity is $a = 120 \ km/h = [tex]\frac{120 * 1000}{3600} = 33.3 \ m/s$ [/tex]

The time taken is $t = 8.28 \ s$

The time taken for contact is $t_c = 0.815 \ s$

The velocity of the of the car after contact is $v_c = 71.0 \ km/h = [tex]\frac{71 *1000}{3600} = 19.7 2 \ m/s$ [/tex]

From the equation of kinematics we have that

$v = u + at$

Here u = 0 \ m/s since the car is initially motionless

=> $33.3 = 0 + a * 8.28$

=> $a = 4.0 \ m/s^2$

4 0

2 years ago

When the compasses are moved close to a wire with a current which will the compasses point

Sindrei [870]

In this demonstration, there is a single compass and a piece of wire that is perpendicular to the plane that the compass sits on. The wire with current flowing through it can alter the direction the compass needle points.

4 0

2 years ago

Read 2 more answers