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grandymaker [24]
3 years ago
11

What happens when an electron absorbs energy?

Chemistry
1 answer:
OLga [1]3 years ago
4 0
The correct answer is A I believe
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The density of lead is 11.3g/cm^3 and the density of chromium is 7.14g/cm^3. If we have one gram of each metal, what is the rati
Lady bird [3.3K]

The ratio of the volume of lead to the volume of chromium is 22 : 35

Density is simply defined as the mass of a substance per unit volume of the substance.

<h3>Density = mass / volume </h3>

To solve the question given above, we'll begin by calculating the volume of lead and chromium. This can be obtained as follow:

<h3>For Lead:</h3>

Mass of lead = 1 g

Density of lead = 11.3 g/cm³

<h3>Volume of lead =? </h3>

Density = mass /volume

11.3 = 1 / Volume

Cross multiply

11.3 × Volume = 1

Divide both side by 11.3

Volume = 1 / 11.3

<h3>Volume of lead = 0.088 cm³</h3>

<h3>For Chromium:</h3>

Mass of chromium = 1 g

Density of chromium = 7.14 g/cm³

<h3>Volume of chromium =? </h3>

Density = mass /volume

7.14 = 1 / Volume

Cross multiply

7.14 × Volume = 1

Divide both side by 7.14

Volume = 1 / 7.14

<h3>Volume of chromium = 0.14 cm³</h3>

Finally, we shall determine the ratio of the volume of lead to the volume chromium. This can be obtained as follow:

Volume of lead = 0.088 cm³

Volume of chromium = 0.14 cm³

<h3>Ratio of the volume of lead to chromium =? </h3>

Ratio = Volume of lead / Volume of chromium

Ratio = 0.088 / 0.14

Ratio = 22 / 35

<h3>Ratio = 22 : 35</h3>

Therefore, the ratio of the volume of lead to the volume chromium is 22 : 35

Learn more: brainly.com/question/17262276

5 0
3 years ago
How many grams of sodium nitrate. NaNO3, are soluble in 100
natka813 [3]

Answer:

Your correct answer is D. 40 g

Explanation:

Please mark brainliest!

4 0
3 years ago
Read 2 more answers
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
2 years ago
Water can be made using the reversible reaction shown. Which change would
Ghella [55]

Decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

As we know that rate of reaction is directly proportional to the concentration of the reactant.

If we increase the concentration of H2 then the rate of reaction increases. So, we keep it constant. Therefore this option is wrong.

By removing the H₂O from the reaction vessel as it almost make no change in the reaction. This can be pursuited the reaction in which product again converted into product.

By increasing the temperature we increases the rate of reaction and equilibrium shift in the forward direction.

Thus, we concluded that by decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

learn more about rate of reaction:

brainly.com/question/8592296

#SPJ13

5 0
11 months ago
Based on the equation, how many grams of Br2 are required to react completely with 72.4 grams of AlCl3
svlad2 [7]

Answer:  131 g of bromine is required.

Explanation:

The balanced equation will be :

2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of AlCl_3

\text{Number of moles}=\frac{72.4g}{133g/mol}=0.544moles

According to stoichiometry :

2 moles of AlCl_3 require  = 3 moles of Br_2

Thus 0.544 moles of AlCl_3 require=\frac{3}{2}\times 0.544=0.816moles  of Br_2

Mass of Br_2=moles\times {\text {Molar mass}}=0.816moles\times 160g/mol=131g

Thus 131 g of bromine is required.

5 0
2 years ago
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