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2 years ago

Which conditions are necessary for clouds to form?

2 answers:

7 0

Answer: Some of the thing that are important for clouds to form are: Moisture - There must be sufficient water vapor in the air for a cloud to form. Cooling air - The air temperature must decrease enough for water vapor to condense

Explanation:

sattari [20]2 years ago

3 0

Answer:

3 conditions necessary for clouds to form are moisture, cooling air, & condensation nuclei. If the conditions are right, then a cloud will form.

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Use absolute dating in a sentence

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Answer:

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2 years ago

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Explain why machine can"t be <br>100% efficient practically?

Zigmanuir [339]

Answer:

Heat

Explanation:

Heat is the main component in why everything is not 100% efficient. Heat is a byproduct of everything and cannot be avoided.

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2 years ago

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If you are at latitude 43 degrees north of Earth's equator, what is the angular distance (in degrees) from your zenith to the no

kirill115 [55]

Answer:

Your zenith is 43 N of 90 deg (equator)

Thus, your zenith is 90 - 43 = 47 deg

(At the N pole your zenith would be 0 deg from the N pole)

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1 year ago

Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j

AlekseyPX

1) Fundamental units of $\Psi$ are $[\frac{mol}{m\cdot s^2}]$

2) Fundamental units of $\Phi$ are $[\frac{mol}{m^3}]$

Explanation:

The equation for the variable $\rho$ is

$\rho =\frac{2\gamma \Phi+\Psi}{rg}$

where we have:

$\rho$ measured in $[\frac{mol}{ft^3}]$

$\gamma$ measured in $[\frac{J}{kg}]$

$r$ measured in $[in]$

$g$ measured in $[\frac{m}{s^2}]$

We can re-write the equation as

$\rho rg = 2\gamma \Phi + \Psi$

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, $\Psi$ must have the same units of $\rho r g$ . So,

$[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]$

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of $\Psi$ are

$[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]$