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4 years ago

Which conditions are necessary for clouds to form?

2 answers:

7 0

Answer: Some of the thing that are important for clouds to form are: Moisture - There must be sufficient water vapor in the air for a cloud to form. Cooling air - The air temperature must decrease enough for water vapor to condense

Explanation:

sattari [20]4 years ago

3 0

Answer:

3 conditions necessary for clouds to form are moisture, cooling air, & condensation nuclei. If the conditions are right, then a cloud will form.

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A charge feels a 7.89 x 10-7 N force when it moves 2090 m/s at a 29.4° angle to a 4.23 x 10-3 T magnetic field. What is the amou

tamaranim1 [39]

We have that the amount of the charge q is

$q=1.8*10^{-7}$

From the Question we are told that

Force $F=7.89 x*10^{-7}$

Velocity $V=2090m/s$

Angle $\theta=29.4$

Magnetic field $B=4.23 * 10^{-3} T$

Generally, the equation for Force F is mathematically given by

$F=qVBsin\theta\\\\q=\frac{F}{VBsin\theta}$

$q=\frac{7.89 x*10^{-7}}{4.23 * 10^{-3} T*sin29.4*2090m/s}$

$q=1.8*10^{-7}$

In conclusion

The amount of the charge q is

$q=1.8*10^{-7}$

For more information on this visit

brainly.com/question/1470439

6 0

3 years ago

Read 2 more answers

What is the ratio of the intensities and amplitudes of an earthquake P wave passing through the Earth and detected at two points

gavmur [86]

For both cases we will use the proportional values of the distance referring to the amplitude and intensity. Theoretically we know that the intensity is inversely proportional to the square of the distance, while the amplitude is inversely proportional to the distance, therefore,

PART A ) Intensity is inversely proportional to the square of the distance

$Intensity \propto \frac{1}{distance^2}$

Therefore the intensity of the two values would be

$\frac{I_{27}}{I_{13}} = \frac{(13km)^2}{(27km)^2}$

$\mathbf{\therefore \frac{I_{27}}{I_{13}} = 0.232 }$

PART B) Amplitude is inversely proportional to the distance

$Amplitude \propto \frac{1}{distance}$

$\frac{A_{27}}{A_{13}}= \frac{(13km)}{(27km)}$

$\mathbf{\therefore\frac{A_{27}}{A_{13}}= 0.4815}$

5 0

3 years ago

A 2578-kg van runs into the back of a 825-kg compact car at rest. They move off together at 8.5 m/s. Assuming the friction with

allochka39001 [22]

Answer:

The initial speed of the car = 11.22 m/s

Explanation:

Law of conservation of energy: It states that when two bodied collide in a closed system, the sum of momentum before collision is equal to the sum of momentum after collision.

Note: A close system is one that is free from from external forces. E.g Frictional force.

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

m₁u₁ + m₂u₂ = (m₁ + m₂)V..................... Equation 1

Where m₁ = mass of the van, m₂ = mass of the car, u₁ = initial velocity of the van, u₂ = initial velocity of the car, V = Common velocity.

Given: m₁ = 2578 kg, m₂ = 825 kg, u₂ = 0 ( the car was at rest), V= 8.5 m/s

Substituting these values into equation 1, and solving for u₁

2578(u₁) + (825 × 0) = (2578 + 825)8.5

2578u₁ = 28925.5

Dividing both side of the equation by the coefficient of u₁

2578u₁/2578 = 28925.5/2578

u₁ = 11.22 m/s

The initial speed of the car = 11.22 m/s

3 0

4 years ago

The gravity of Earth is attracting a person towards the center with 500N of gravitational force. The person is exerting a reacti

Maru [420]

The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me

6 0

3 years ago

2. A mixing bowl has a mass of 0.5kg. A baker adds 0.0002m of water to the mixing bowl until

myrzilka [38]

Answer:

mass of water is 0.2kg

Explanation:

mass of water is tota mass of bowl minus mass of bowl

6 0

2 years ago