Bruh ima be honest with you idek
Answer:
Asch (1956) found that group size influenced whether subjects conformed. The bigger the majority group (no of confederates), the more people conformed, but only up to a certain point.
Explanation:
Answer:
2.86×10⁻¹⁸ seconds
Explanation:
Applying,
P = VI................ Equation 1
Where P = Power, V = Voltage, I = Current.
make I the subject of the equation
I = P/V................ Equation 2
From the question,
Given: P = 0.414 W, V = 1.50 V
Substitute into equation 2
I = 0.414/1.50
I = 0.276 A
Also,
Q = It............... Equation 3
Where Q = amount of charge, t = time
make t the subject of the equation
t = Q/I.................. Equation 4
From the question,
4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs
Q = 7.899×10⁻¹⁹ C
Substitute these value into equation 4
t = 7.899×10⁻¹⁹/0.276
t = 2.86×10⁻¹⁸ seconds
Answer:
B) (-2.0 m, 0.0 m)
Explanation:
Given:
Mass of particle 1 is, ![m_1=2.0\ kg](https://tex.z-dn.net/?f=m_1%3D2.0%5C%20kg)
Mass of particle 2 is, ![m_2=3.0\ kg](https://tex.z-dn.net/?f=m_2%3D3.0%5C%20kg)
Position of center of mass is, ![(x_{cm},y_{cm})=(0,0)](https://tex.z-dn.net/?f=%28x_%7Bcm%7D%2Cy_%7Bcm%7D%29%3D%280%2C0%29)
Position of particle 1 is, ![(x_1,y_1)=(3.0\ m,0.0\ m)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%283.0%5C%20m%2C0.0%5C%20m%29)
Position of particle 2 is, ![(x_2,y_2)=(?\ m,?\ m)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%3D%28%3F%5C%20m%2C%3F%5C%20m%29)
We know that, the x-coordinate of center of mass of two particles is given as:
![x_{cm}=\frac{m_1x_1+m_2x_2}{m_1+m_2}](https://tex.z-dn.net/?f=x_%7Bcm%7D%3D%5Cfrac%7Bm_1x_1%2Bm_2x_2%7D%7Bm_1%2Bm_2%7D)
Plug in the values given.
![0=\frac{(2.0\times 3)+(3.0\times x_2)}{2.0+3.0}\\\\0=6+3x_2\\\\3x_2=-6\\\\x_2=\frac{-6}{3}=-2.0\ m](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B%282.0%5Ctimes%203%29%2B%283.0%5Ctimes%20x_2%29%7D%7B2.0%2B3.0%7D%5C%5C%5C%5C0%3D6%2B3x_2%5C%5C%5C%5C3x_2%3D-6%5C%5C%5C%5Cx_2%3D%5Cfrac%7B-6%7D%7B3%7D%3D-2.0%5C%20m)
We know that, the y-coordinate of center of mass of two particles is given as:
![y_{cm}=\frac{m_1y_1+m_2y_2}{m_1+m_2}](https://tex.z-dn.net/?f=y_%7Bcm%7D%3D%5Cfrac%7Bm_1y_1%2Bm_2y_2%7D%7Bm_1%2Bm_2%7D)
Plug in the values given.
![0=\frac{(2.0\times 0)+(3.0\times y_2)}{2.0+3.0}\\\\0=0+3y_2\\\\3y_2=0\\\\y_2=\frac{0}{3}=0.0\ m](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B%282.0%5Ctimes%200%29%2B%283.0%5Ctimes%20y_2%29%7D%7B2.0%2B3.0%7D%5C%5C%5C%5C0%3D0%2B3y_2%5C%5C%5C%5C3y_2%3D0%5C%5C%5C%5Cy_2%3D%5Cfrac%7B0%7D%7B3%7D%3D0.0%5C%20m)
Therefore, the position of particle 2 of mass 3.0 kg is (-2.0 m, 0.0 m).
So, option (B) is correct.
That seems like a statement more than a question. Where's the question?