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3 years ago

Hazel recently read an article that claimed that radio waves can cause electron displacement. Based on

Physics

1 answer:

iren [92.7K]3 years ago

3 0

Answer:

Based on the passage, the article's claim is not true. Therefore, the answer is:

No, because radio waves have energies that are too low to fall in the ionizing range.

Explanation:

Radio waves are generally known as forms of non-ionizing radiation. This means that they do not have enough energy, unlike microwaves, to separate electrons from atoms or molecules, thereby ionizing them. They cannot cause electron displacement, as claimed in the article. Therefore, they cannot break chemical bonds, which can cause chemical reactions or DNA damage. As non-ionizing radiation, radio waves occur at lower frequencies in the electromagnetic spectrum.

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An object oscillates with an angular frequency of 8.0 rad/s. At t = 0, the object is at x0 = 4 cm with an initial velocity v0 =

KatRina [158]

Answer:

$\phi = 0.66 rad$

$A = 5.06 cm$

Explanation:

We have here a simple harmonic motion, so the equation of the position in this motion is:

$x(t)=Acos(\omega t+\phi)$ (1)

A: Amplitude

ω: angular frequency

φ: phase constant

If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

$v(t)=\frac{dx(t)}{dt}=-A\omega sin(\omega t+\phi)$ (2)

Let's evaluate (1) and (2) in t=0.

$x(0)=Acos(\phi)$ (3)

$v(0)=-A\omega sin(\phi)$ (4)

Dividing 4 by 3 we have:

$\frac{v(0)}{x(0)}=-\omega tan(\phi)$

$\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})$

$\phi = 0.66 rad$

Now, using (3) we can find the amplitude.

$A = \frac{x(0)}{cos(\phi)} = 5.06 cm$

I hope it helps!

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1 year ago