Question

A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in a lettuce garden to another location, with position vector 2,=3.65 m and 2,=−4.79 m, where the lettuce appears to be tastier (but really is not; this turtle cannot see very well). The excursion takes 304 s to complete. What are the components and the magnitude of the turtle's average velocity in meters per second?

Answer 1

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

$d_x = 3.65-1.91=1.74 m$

While the displacement in the y-direction is:

$d_y = -4.79 -(-2.73)=-2.06 m$

The time taken is t = 304 s.

So the components of the average velocity are:

$v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s$

$v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s$

And the magnitude of the average velocity is

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s$