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3 years ago

What form of energy transforms to what other form when you turn on a steam iron?

Physics

2 answers:

timama [110]3 years ago

4 0

Electrical energy to thermal energy

Likurg_2 [28]3 years ago

4 0

The form of energy transforms to what other form when you turn on a steam iron is the conversion of
ELECTRICAL ENERGY TO THERMAL ENERGY
As it contains most particles
so i conclude option D is correct
hope it helps

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2. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this wee

Alex17521 [72]

Answer:

62 seconds
no

Explanation:

The total travel time Suzette experiences is the sum of the times in each hallway. Using

time = distance/speed

we can add the times.

(35.0 m)/(3.50 m/s) +(48.0 m)/(1.20 m/s) +(60 m)/(5.0 m/s)

= 10 s + 40 s + 12 s

= 62 s

It takes Suzette 62 seconds to get to class. She does not beat the bell.

3 0

4 years ago

Two charges, X and Y, are placed along the x-axis. Charge X is +18 nC and is placed at x = 0. Charge Y is placed at a location o

Helen [10]

Answer:

Charge Z can be placed at x = -2.7 m or at x = 0.27 m.

Explanation:

The Coulomb force between two charges, $Q_1$ and $Q_2$ , separated by a distance, $d$ , is given

$F = k\dfrac{Q_1Q_2}{r^2}$

k is a constant.

For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.

It is to be placed along the x-axis. Hence, it is on the same line as charges X and Y.

Let the charge on Z be Q. It is positive.

Let the distance from charge X be x m. Then the distance from charge Y will be (0.60 - x) m.

Force due to charge X

$F_X = k\dfrac{18Q}{x^2}$

Force due to charge Y

$F_Y = k\dfrac{-27Q}{(0.60-x)^2}$

Since both forces are equal and opposite,

$F_X = -F_Y$

$k\dfrac{18Q}{x^2} = -k\dfrac{-27Q}{(0.60-x)^2}$

$\dfrac{2}{x^2} = \dfrac{3}{(0.60-x)^2}$

$2(0.60-x)^2 = 3x^2$

$2(0.36-1.20x+x^2) = 3x^2$

$0.72-2.40x+2x^2 = 3x^2$

$x^2+2.40x-0.72 = 0$

Applying the quadratic formula,

$x = \dfrac{-2.40\pm\sqrt{2.40^2 - (4)(1)(-0.72)}}{2} = \dfrac{-2.40\pm\sqrt{8.64}}{2}$

$x = -2.7$ or $x = 0.27$

Charge Z can be placed at x = -2.7 m or at x = 0.27 m

3 0

4 years ago

(a) a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerte

Musya8 [376]

The dimension of force, F is ML/T².

<h3>What is force?</h3>

Force is a push o push agent which causes a change in the state of rest or motion of an object.

From a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerted on the object and inversely proportional to its mass.

Mathematically; acceleration ∝ F/m

F = ma

dimension of Mass = M

dimension of acceleration = L/T²

dimension of force, F = ML/T²

In conclusion, the dimension of force is obtained from the dimensions of mass and acceleration.

Learn more about dimension of force at: brainly.com/question/28243574

#SPJ1

5 0

2 years ago

What is the root mean square speed of an As4 particle as it is sublimed? (Assume at high temperatures arsenic acts like an ideal

Norma-Jean [14]

Answer: $v_{rms} =$ 273m/s

Explanation: Root Mean Square Speed of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.

It can be calculated:

$\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T$

$v^{2} = \frac{3k_{B}T}{m}$

$v = \sqrt{\frac{3k_{B}T}{m}}$

m is mass of one atom or molecule in kg.

An atom of Arsenic sublimes at 614°C. Converting to Kelvin:

T = 614 + 273 = 887K

Molecular mass of As4 is approximately 0.3kg.

$m = \frac{0.3}{6.10^{23}}$

$m=5.10^{-25}$ kg

Calculating Root mean square speed :

$v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}$

$v = \sqrt{745.08.10^{2}$

v = 273m/s

The root mean square speed of As4 is approximately 273m/s.

5 0

3 years ago

A 1-hectare field contains 2500 bean plants having a total leaf surface area of 557 m2. ambient temperature is 21Â°c, winds are

Mashcka [7]

Answer:

The field losses a total of 55.814 litres of water in an hour.

Explanation:

As the complete question is not given here, the average rate of water loss is not given here which is found in normal conditions as 1.67 mL/m2.

Now the average rate of water loss per minute is 1.67 mL/m2

So the average rate of water loss per minute for 557 m2 is 1.67*557=930.19 mL

So 930.19 mL of water is lost from the field in 1 minute, for the calculation of water lost in an hour, the value is given as 60*930.19 =55811.4 mL or 55.814 litres.

8 0

4 years ago