Answer:
4.16 L
Explanation:
Assuming constant temperature,
At the edge of Typhoon Odessa: P₁ = 1 atm = 1013.3 mbar,
V₁ = 4.0 L
At the center of Typhoon Odessa: P₂ = (1013.3 - 40.0) mbar = 973.3 mbar
V₂ = ? L
For a fixed amount of gas at constant temperature (Boyle's law) : P₁V₁ = P₂V₂
V₂ = V₁ × (P₁/P₂)
V₂= (4.0) × (1013.3/973.3)
V₂= 4.16 L
Answer:
7200 kg.m/s
Explanation:
According the law of conservation of linear momentum, the sum of momentum before and after collision are equal.
Using this principle, the sum of initial momentum will be given as p=mv where p is momentum, m is mass and v is velocity
Initial momentum
Mass of whale*initial velocity of whale + mass of seal*initial seal velocity
Since the seal is initially stationary, its velocity is zero. By substitution and taking right direction as positive
Initial momentum will be
1200*6+(280*0)=7200 kg.m/s
Since both initial and final momentum should be equal, hence the final momentum will also be 7200 kg.m/s
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