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Klio2033 [76]
3 years ago
5

What form of energy transforms to what other form when you turn on a steam iron?

Physics
2 answers:
timama [110]3 years ago
4 0
Electrical energy to thermal energy
Likurg_2 [28]3 years ago
4 0
<span> The form of energy transforms to what other form when you turn on a steam iron is the conversion of
</span>ELECTRICAL ENERGY TO THERMAL ENERGY
As it contains most particles 
so i conclude option D is correct
hope it helps
You might be interested in
2. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this wee
Alex17521 [72]

Answer:

  • 62 seconds
  • no

Explanation:

The total travel time Suzette experiences is the sum of the times in each hallway. Using

  time = distance/speed

we can add the times.

  (35.0 m)/(3.50 m/s) +(48.0 m)/(1.20 m/s) +(60 m)/(5.0 m/s)

  = 10 s + 40 s + 12 s

  = 62 s

It takes Suzette 62 seconds to get to class. She does not beat the bell.

3 0
4 years ago
Two charges, X and Y, are placed along the x-axis. Charge X is +18 nC and is placed at x = 0. Charge Y is placed at a location o
Helen [10]

Answer:

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m.

Explanation:

The Coulomb force between two charges, Q_1 and Q_2, separated by a distance, d, is given

F = k\dfrac{Q_1Q_2}{r^2}

<em>k</em> is a constant.

For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.

It is to be placed along the <em>x</em>-axis. Hence, it is on the same line as charges X and Y.

Let the charge on Z be <em>Q</em>. It is positive.

Let the distance from charge X be <em>x m.</em> Then the distance from charge Y will be (0.60 - <em>x</em>) m.

Force due to charge X

F_X = k\dfrac{18Q}{x^2}

Force due to charge Y

F_Y = k\dfrac{-27Q}{(0.60-x)^2}

Since both forces are equal and opposite,

F_X = -F_Y

k\dfrac{18Q}{x^2} = -k\dfrac{-27Q}{(0.60-x)^2}

\dfrac{2}{x^2} = \dfrac{3}{(0.60-x)^2}

2(0.60-x)^2 = 3x^2

2(0.36-1.20x+x^2) = 3x^2

0.72-2.40x+2x^2 = 3x^2

x^2+2.40x-0.72 = 0

Applying the quadratic formula,

x = \dfrac{-2.40\pm\sqrt{2.40^2 - (4)(1)(-0.72)}}{2} = \dfrac{-2.40\pm\sqrt{8.64}}{2}

x = -2.7 or x = 0.27

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m

3 0
4 years ago
(a) a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerte
Musya8 [376]

The dimension of force, F is ML/T².

<h3>What is force?</h3>

Force is a push o push agent which causes a change in the state of rest or motion of an object.

From a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerted on the object and inversely proportional to its mass.

Mathematically; acceleration ∝ F/m

F = ma

dimension of Mass = M

dimension of acceleration = L/T²

dimension of force, F = ML/T²

In conclusion, the dimension of force is obtained from the dimensions of mass and acceleration.

Learn more about dimension of force at: brainly.com/question/28243574

#SPJ1

5 0
2 years ago
What is the root mean square speed of an As4 particle as it is sublimed? (Assume at high temperatures arsenic acts like an ideal
Norma-Jean [14]

Answer: v_{rms} = 273m/s

Explanation: <u>Root</u> <u>Mean</u> <u>Square</u> <u>Speed</u> of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.

It can be calculated:

\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T

v^{2} = \frac{3k_{B}T}{m}

v = \sqrt{\frac{3k_{B}T}{m}}

m is mass of one atom or molecule in kg.

An atom of Arsenic sublimes at 614°C. Converting to Kelvin:

T = 614 + 273 = 887K

Molecular mass of As4 is approximately 0.3kg.

m = \frac{0.3}{6.10^{23}}

m=5.10^{-25}kg

Calculating Root mean square speed :

v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}

v = \sqrt{745.08.10^{2}

v = 273m/s

<u>The root mean square speed of As4 is approximately </u><u>273m/s</u><u>.</u>

5 0
3 years ago
A 1-hectare field contains 2500 bean plants having a total leaf surface area of 557 m2. ambient temperature is 21°c, winds are
Mashcka [7]

Answer:

The field losses a total of 55.814 litres of water in an hour.

Explanation:

As the complete question is not given here, the average rate of water loss is not given here which is found in normal conditions as 1.67 mL/m2.

Now the average rate of water loss per minute is 1.67 mL/m2

So the average rate of water loss per minute for 557 m2 is 1.67*557=930.19 mL

So 930.19 mL of water is lost from the field in 1 minute, for the calculation of water lost in an hour, the value is given as  60*930.19 =55811.4 mL or 55.814 litres.

8 0
4 years ago
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