The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
<h3>Parallel force on the patient</h3>
The parallel force on the patient is calculated as follows;
F = mg sinθ
F = (75 x 9.8) x sin(12)
F = 152.82 N
<h3>Average power required </h3>
P = FV
where;
- V is speed = 3.1 km/h = 3.1/3.6 = 0.861 m/s
F = 152.82 x 0.861
F = 131.58 W
Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
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Answer:
Wouldn't it be 17.5. Force doubles in weight.
Explanation:
Do you have the options? I would say swerve?
