Ask question

Ask question

All categories

3 years ago

14

If earth stops rotating then what will be the value of 'g' at poles

1 answer:

Marianna [84]3 years ago

7 0

The value of 'g' is not affected by rotation at any place on Earth.

You might be interested in

Suppose multiple stations are connected in wired network where CSMA/CD implemented. Among them, station A wants to communicate w

anastassius [24]

Answer:

bro i think ur from the uni of arid agriculture rawalpindi and today is your networking paper

Explanation:

6 0

3 years ago

What does it mean to say something is proportional?

mamaluj [8]

Answer: When quantities have the same relative size. In other words they have the same ratio corresponding in size or amount to something else.

Explanation: Example: "A rope's length and weight are in proportion."

Example: "The punishment should be proportional to the crime"

4 0

3 years ago

Which of the following statements describes nucleons?

Yuliya22 [10]

The correct answer is D.

A nucleon<span> is one of either of the two types of subatomic particles (neutrons and protons) which are located in the nucleus of atoms.
</span>

The total number of nucleon in the nucleus of an atom gives you an idea about the mass of that atom. In fact, one may refer mass number as nucleon number.

Simply put, nucleons are the particles that make nucleus of an atom and are held up together inside the nucleus due to nuclear force.

7 0

3 years ago

Read 2 more answers

Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its

ruslelena [56]

Answer:

a

The orbital speed is $v= 2.6*10^{3} m/s$

b

The escape velocity of the rocket is $v_e= 3.72 *10^3 m/s$

Explanation:

Generally angular velocity is mathematically represented as

$w = \frac{2 \pi}{T}$

Where T is the period which is given as 1.6 days = $1.6 *24 *60*60 = 138240 sec$

Substituting the value

$w = \frac{2 \pi}{138240}$

$= 4.54*10^ {-5} rad /sec$

At the point when the rocket is on a circular orbit

The gravitational force = centripetal force and this can be mathematically represented as

$\frac{GMm}{r^2} = mr w^2$

Where G is the universal gravitational constant with a value $G = 6.67*10^{-11}$

M is the mass of the earth with a constant value of $M = 5.98*10^{24}kg$

r is the distance between earth and circular orbit where the rocke is found

Making r the subject

$r = \sqrt[3]{\frac{GM}{w^2} }$

$= \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }$

$= 5.78 *10^7 m$

The orbital speed is represented mathematically as

$v=wr$

Substituting value

$v= (5.78*10^7)(4.54*10^{-5})$

$v= 2.6*10^{3} m/s$

The escape velocity is mathematically represented as

$v_e = \sqrt{\frac{2GM}{r} }$

Substituting values

$= \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }$

$v_e= 3.72 *10^3 m/s$

7 0

3 years ago

A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k

svlad2 [7]

The terminal speed of the marble is 0.588 m/s.

<h3>Calculation:</h3>

We know that,

F = mg ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

Hence, the terminal speed of the marble is 0.588 m/s.

Learn more about calculation of force here:

brainly.com/question/15562875

#SPJ4

.

5 0

2 years ago

Read 2 more answers