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3 years ago

Anika asks Eva to roll a basketball and then a bowling

Physics

1 answer:

Alex73 [517]3 years ago

8 0

Answer:

the bowling ball, because it has more mass and therefore more inertia

Explanation:

As per law of inertia we know that if an object is having more inertia then it is difficult to change state of motion.

Inertia is the property of mass of an object which always resist to change the state of motion of the object.

If an object has more inertia then it is more difficult to change the state of motion.

Now we know that we have one bowling ball and one basket ball, since bowling ball is having more mass then it must have more inertia so it is difficult to start the motion in bowling ball.

So correct answer will be

the bowling ball, because it has more mass and therefore more inertia

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Answer:

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Explanation:

The general equation to calculate the center of mass is:

$r_{cm}=1/M*\int\limits {r} \, dm$

Any differential of mass can be calculated as:

$dm = \lambda*a*d\theta$ Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

$\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}$

So, the differential of mass is:

$dm = \frac{2M}{a\pi}*a*d\theta$

$dm = \frac{2M}{\pi}*d\theta$

Now we proceed to calculate X and Y coordinates of the center of mass separately:

$X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta$

$Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta$

Solving both integrals, we get:

$X_{cm}=2*a/\pi=12.73cm$

$Y_{cm}=2*a/\pi=12.73cm$

Therefore, the position of the center of mass is:

$r_{cm}=[12.73,12.73]cm$

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