Answer:
0
Explanation:
m = Mass of person
g = Acceleration due to gravity = 9.81 m/s²
d = Vertical height from the ground
F = Force = Weight = mg
Net work done would be

Hence, the work done on the person by the gravitational force is 0
Answer:
if somthing is warm or if somthing moves it usally has energy
B is the awser
good luck and hope it helps
Answer:
1902.75 kg
Explanation:
From Law of conservation of momentum,
m₁u₁ + m₂u₂ = V (m₁ + m₂).................... Equation 1
make m₂ the subject of the equation,
m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2
Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity
Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)
Substituting into equation 2.
m₂ =[2537(8) - 2537(14)]/(0-8)
m₂ = (20296-35518)/-8
m₂ = -15222/-8
m₂ = 1902.75 kg.
Thus the mass of the car = 1902.75 kg
Hi there!
Acceleration:
a = Δv / Δt, so:
a = 20/9 ≈ 2.22 m/s²
Displacement:
We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).
Δd = 1/2at²
Plug in the acceleration and time:
Δd = 1/2(2.22)(9)² ≈ 89.91 m