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3 years ago

5

Soot particles ("black carbon aerosols" generally cause of earth's atmosphere by solar energy.

1 answer:

matrenka [14]3 years ago

8 0

They cause an increase in temp of earths atmosphere or warming by absorbing solar energy. hope this helps

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On what factors does critical velocity depend on

ASHA 777 [7]

Explanation:

The critical velocity is that velocity of liquid flow, up to which its flow is streamlined (laminar)& above which its flow becomes turbulent. It's denoted by Vc & it depends upon: Coefficient of viscosity of liquid (η) Density of liquid. Radius of the tube.

6 0

3 years ago

If the temperature of water warming on a hot plate rises 10 degrees Celsius [°C], what is the change in temperature in units of

Luba_88 [7]

Answer:

Delta_temp = 18[°F]

Explanation:

°F = 9/5*(10)

°F = 18

Note: It is important to clarify that it is only a temperature increase, that it is only a temperature increase. The question is not related to converting from 10°C to fahrenheit degrees

4 0

3 years ago

Pls help me I don’t get it :(

Ksju [112]

Answer:

2nd and 4th

Explanation:

4 0

3 years ago

Find the hiker’s gravitational potential energy if the cliff is 60m high

Furkat [3]

Answer:

Potential energy is $U=mgh$

Explanation:

The potential energy depends on the mass, the acceleration of gravity g and the height at which the object or person is.

Potential energy $U=mgh$

In this case we would need to know the exact mass of the hiker in order to calculate the potential energy.

But we know the values of g and h

$g=9.81m/s^2$

$h=60m$

So, the potential energy

$U=m(9.81m/s^2)(60m)\\\\U=588.6*m$

m is the mass of the hiker, wich is not in the description of the problem.

4 0

3 years ago

In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48

cluponka [151]

Answer:

The thickness is $\Delta y = 2.4 *10^{-6} \ m$

Explanation:

From the question we are told that

The wavelength is $\lambda = 480 \ nm = 480*10^{-9} \ m$

The first order of the dark fringe is $m_1 = 16$

The second order of dark fringe considered is $m_2 = 6$

Generally the condition for destructive interference is mathematically represented as

$y = \frac{m \lambda}{2}$

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

$y_1 - y_2 = \Delta y = \frac{m_1 \lambda}{2} - \frac{m_2 \lambda}{2}$

=> $y_1 - y_2 = \Delta y = \frac{16 *480*10^{-9}}{2} - \frac{6 *480*10^{-9}}{2}$

=> $y_1 - y_2 = \Delta y = 5 (480*10^{-9})$

=> $\Delta y = 2.4 *10^{-6} \ m$

8 0

3 years ago