A book falls to the floor.
A car skids to a stop.
A foam ball launches from a spring (Are the right answer, just did this one 4:34 pm Jan/21/19)
To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ
sec θ = 1 / cos <span>θ
csc </span>θ = 1 / sin θ<span>
Using these identities:
</span>cot θ ∙ sec θ = (cos θ / sin θ ) (<span> 1 / cos </span><span>θ)
</span>
We can cancel out cos <span>θ, leaving us with
</span>cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc <span>θ</span>
Answer:
Work to move on ion inside a cell = 1.168×10^-20J
Explanation:
Potential difference is a ratio of work done by a charge.
It is given as
◇V= Workdone ×charge= W/a
Workdone = V × q= (7.3×10^-2)×(1.6×10^-19)
W= 1.168×10^-20Joules
The gravitational potential energy U is defined as the product of mass m, the acceleration of gravity g and the height of object h.

We do not have the mass of the hiker. But we know that its W weight is:

Where

So:
.
So:

J
The hiker has gained 30,000 J of energy
Answer:
1.5 x 10⁵ W
Explanation:
A = Area of the fresh lava = 1.02 m²
T = Temperature of fresh lava = 1000 °C = 1000 + 273 = 1273 K
T₀ = Temperature of surrounding = 25.3 °C = 25.3 + 273 = 298.3 K
ε = emissivity of the lava = 0.97
σ = stefan's constant = 5.67 x 10⁻⁸ Wm⁻²K⁻⁴
Rate of transfer is given as
E = σ ε A (T⁴ - T₀⁴)
E = (5.67 x 10⁻⁸) (0.97) (1.02) ((1273)⁴ - (298.3)⁴)
E = 1.5 x 10⁵ W