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miv72 [106K]
3 years ago
5

What is the main fuel consumed in the core of a red giant? a. H b. C c. Fe d. He

Physics
1 answer:
vladimir1956 [14]3 years ago
4 0
<span>What is the main fuel consumed in the core of a red giant?
The </span><span>main fuel consumed in the core of a red giant is He or helium. The answer is letter D.</span>
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Anyone wanna chitchat? i'm just bored
Mashcka [7]

Answer:

yea me too you know your question is gunna get deleted bc it is not school related but I'm not gunna report it or anything

Explanation:

5 0
3 years ago
Which situation is the best example of translational motion? Question 1 options: a coin spinning on a desk a leaf blowing across
lukranit [14]

Translational motion is a type of motion in which objects move with a change in position. The situation that best shows the translational motion is leaf blowing in the field.

Translational Motion:

It is a type of motion in which objects move with a change in position.

For example- leaf blowing in the field.

  • Coin spinning on the desk does not change its position.
  • A car in the parking lot with running engine does not change its position.
  • Standing in feet is not any kind of movement.

Therefore, the situation that best shows the translational motion is leaf blowing in the field.

Learn more about Translational Motion:

brainly.com/question/2416005

7 0
3 years ago
Facts about conolizing into mars?​
Leto [7]

Answer:

xxxx

Explanation:

Mars also has a thin atmosphere. Because of this it has potential to host humans and other organic life. That makes Mars the best choice for thriving colony off the earth. The moon has also been proposed as the first location for human colonization but it not known to have air or water.

Hope this helps!

Have an amazing day/night

7 0
3 years ago
An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them
Alexandra [31]

Answer:

1 / i + 1 / o = 1 / f     thin lens equations

i = o f / (o - f)   rearranging

Lens 1:   object = 30 cm    f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm    distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

7 0
3 years ago
Hook's law describes an ideal spring. Many real springs are better described by the restoring force (FSp)s=−kΔs−q(Δs)^3, where q
kvasek [131]

Answer

given,

k = 250 N/m

q = 900 N/m³

(FSp)s=−kΔs−q(Δs)^3

work done = Force x displacement

W = \int {F. dx}

limits are x = 0 to x = 0.15 m

work done

W = \int_0^{0.15} (k x + q x^3)\ dx

W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15

W = \dfrac{300\times 0.15^2}{2}+\dfrac{900\times 0.15^4}{4}

W = 3.375 + 0.1139

W = 3.3488 J

b) % cubic term =\dfrac{0.1139}{3.3488}

   % cubic term =3.4\ %

7 0
3 years ago
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