Answer:
27000 Nm
Explanation:
The boom end at A is fixed and end at B is subjected to a 3kN force. Boom AB has length of 9m. The moment about A is the product of force 3kN (3000 N) at B and the moment arm of 9m
M = FL = 3000 * 9 = 27000 Nm
So the moment about A is 27000 Nm
The energy delivered by the laser in 1 second is

In order to find how many photons correspond to this energy, we must calculate the energy of a single photon.
Calling h the Planck constant, c the speed of light and

the wavelength of the light, the energy of a single photon is given by

So, the number of photons emitted by the laser in 1 second is equal to the total energy delivered by the laser divided by the energy of a single photon:

photons
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