KE = 1/2 * m * v^2
KE = 1/2 * 0.135 * 40^2
KE = 1/2 * 0.135 * 1600
KE = 108 J
Answer:
The intensity will be 1/9 as much.
Explanation:
The intensity of the light or any source is inversely related to the square of the distance.

Now according to the question the distance is increased by three times than,

Therefore,

Therefore the intensity will become 1/9 times to the initial intensity.
Since bulb is connected in the closed circuit at the position of D
as well as switch B is also closed in that position so the current will flow through the bulb and bulb will glow in that position
So the most appropriate correct option will be
D. The light bulb will be on
B is the correct answer hope that helped
Answer: The answer is B
Explanation: It is staying in a steady speed position