Molarity = mol/liter
0.708M = 0.098mol/L
Rearrange to find L:
0.098mol/0.708M = .138L
For every liter there is 1000 mL:
.138L • 1000mL =138mL KOH
Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79, making it one of the higher atomic number elements that occur naturally. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal.
Answer:
FALSE
Explanation:
The under-water deep ocean currents that are generated due to the differences in the water density are generally termed as the thermohaline circulation. It is mainly controlled by the two factors namely the temperature and the salinity. The word 'thermohaline' is directly derived from the temperature (thermo) and salinity (haline).
This thermohaline circulation is considered as the oceanic conveyor belt that allows the water to move under the surface of water at certain depths from the equator to the poles and back from the poles to the equator.
Thus, it is directly associated with the density of the water. It has no relation with the wind.
Hence, the above statement is False.
Answer:
The answer to your question is 22.4 g of Ca(NO₃)₂
Explanation:
Data
mass of Ca(NO₃)₂ = ?
mass of water = 726 g
concentration = 0.2 m
Process
In Chemistry, there are two main units of concentration Molarity (M) and Molality (m). In this problem concentration is "m" then I will calculate molality.
1) Formula
molality = moles / mass of solvent
2.- Solve for moles
moles = molality x mass of solvent
-Substitution
moles = (0.2) x (0.726)
-Simplification
moles = 0.1452
3.- Convert moles to grams
Molar mass of Ca(NO₃)₂ = 40 + (14 x 2) + (6 x 16)
= 40 + 18 + 96
= 154 g
154 g of Ca(NO₃)₂ ---------------- 1 mol
x ---------------- 0.1452 moles
x = (0.1452 x 154) / 1
x = 22.4 g of Ca(NO₃)₂
