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Firlakuza [10]
3 years ago
5

Which organisms in this food web are carnivores? Select the two correct

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

The two correct options are Poison dart frog and Boa constrictor. Both these organisms are pure carnivores which are also known as pure meat eaters in the food web. Carnivores are organisms in the food chain that only meat-eaters and never take any type of vegetation in their diet.

Explanation:

  • A Poison dart frog purely survives on meat (meat- eater).
  • Long sticky tongues are used to catch their prey such as ants, flies, insects.
  • Since they produce high toxin levels, it has very few predators in the wild.
  • Boa constrictor is also an organism that eats only meat.
  • While they are young they eat prey like rats, squirrels and mice.
  • The type of attack used by a boa constrictor is an ambush attack type. It attacks its preys using the surprise factor.

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The rock outcrop, shown above demonstrates the law of included fragments. Identify the correct definition for the law of include
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Answer:

A

Explanation:

The law of included fragments states: Fragments found in a rock must be older than the rock itself.

7 0
2 years ago
The number placed in front of a compound to balance a chemical reaction is called?
slamgirl [31]

Answer:

coefficients

Explanation:

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3 0
3 years ago
Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to
irga5000 [103]

Sodium carbonate is used to neutralised sulfuric acid, H₂SO₄. Sodium carbonate is the salt of stron base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:

Na₂CO₃ + H₂SO₄→ Na₂SO₄ + H₂CO₃

From balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of  H₂SO₄. Molar mass of Na₂CO₃= 106 g/mol=0.106 kg/mol and molar mass of H₂SO₄= 98 g/mol=0.098 kg/mol.

To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, to neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is=\frac{0.106 X 5.04 X 10^{3} }{0.098} kg= 5.451 X 10³ kg.

5 0
3 years ago
The 85.2-g sample of the compound x4o10 contains 48.0 g of oxygen atoms. what is the molar mass of element x?
Vedmedyk [2.9K]
X4O10
Let molar mass of X be y
molar mass =  4y + 10 x 16 = 4y+160

so, moles = 85.2 / (4y+160)

Moles of oxygen = 10 x [85.2 / (4y+160) ]
Mass of oxygen  = 16 x 10 x [85.2 / (4y+160) ]
which is 48.0

so, 48 = 16 x 10 x [85.2 / (4y+160) ]

Solve the equation to get y.

y = 31
5 0
3 years ago
Give the formula of the conjugate base of HSO4–
mr Goodwill [35]
The answer is So^2-4
7 0
3 years ago
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