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2 years ago

What is the volume of 3.00 mole of ideal gas at 100.0 C and 2.00 kPa

Chemistry

1 answer:

Novosadov [1.4K]2 years ago

8 0

Answer:

The volume for the ideal gas is: 4647.5 Liters

Explanation:

Formula for the Ideal Gases Law must be applied to solve this question:

P . V = n . R . T

We convert the T° to K → 100°C + 273 = 373 K

We convert pressure value from kPa to atm.

2 kPa . 1atm/101.3 kPa = 0.0197 atm

We replace data in the formula.

V = ( n . R . T) / P → (3 mol . 0.082 . 373K) / 0.0197 atm =

The volume for the ideal gas is: 4647.5 Liters

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3 years ago

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Question 2: Heat (5 points)

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3 years ago

An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is

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Answer:

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

Explanation:

The gas ideal law is

PV= nRT (equation 1)

Where:

P = pressure

R = gas constant

T = temperature

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$n =\frac{PV}{RT}$

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$T =\frac{T_{1} + T_{O}}{2}$

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$m =\frac{P*V*mw}{R*T}$ (equation 2)

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