Sorry but I only know a few
17- decomposers
18- decomposition
21- 10% is lost so 90%
I think the effect of increasing temperature would be; the equilbrium will shift back wards. Increase in temperature favors backward reaction since the forward reaction is exothermic and the backward reaction is endothermic. Therefore, the equilibrium will shift back wards, and there will be more reactants (H2 and Cl2) compared to the products
Answer:
C
Explanation:
<em>The </em><em>specific</em><em> </em><em>heat </em><em>capacity</em><em>=</em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>in </em><em>joule/</em><em>mass×</em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in </em><em>temperature</em>
<em>from </em><em>this </em><em>question</em><em> </em><em>the </em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>is </em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>,</em><em>the </em><em>mass </em><em>is </em><em>2</em><em>0</em><em>0</em><em>0</em><em> </em><em>and </em><em>the </em><em>change </em><em>in </em><em>temperature</em><em> </em><em>is </em><em>5</em><em>0</em><em>-</em><em>3</em><em>0</em>
<em>which </em><em>is </em><em>2</em><em>0</em>
<em>therefore</em>
<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>2</em><em>0</em><em>0</em><em>0</em><em>×</em><em>2</em><em>0</em>
<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>4</em><em>0</em><em>0</em><em>0</em><em>0</em>
<em>c=</em><em>1</em><em>.</em><em>8</em><em>8</em>
<em>I </em><em>hope </em><em>this </em><em>helps</em>
The solution that will have the lowest freezing point is 5.0 SODIUM CHLORIDE.
Adding solute to solvents usually result in the depression of the freezing point. The higher the quantity of the solute that is added, the lower the freezing point of the solution.
The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
Molarity = no of moles/volume
According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.
no.of moles of CuSO4 = 35g ÷ 159.6g/mol
no. of moles of CuSO4 = 0.22 moles
Therefore; molarity of CuSO4 solution is calculated as follows:
M = 0.22 ÷ 0.25
M = 0.88M
Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.
Learn more about molarity at: brainly.com/question/12127540
