Cu+ p=29 e=28 n=34
S2- p=16 e=18 n=16
Pb4+ p=82 e=78 p=125
I hope i did it right :))
I’m not sure if this is what you are referring to but there is something called a moles bridge which allows you to convert from one substance to another
Explanation:
The given data is as follows.
Refractive index of mixture = 1.456
Refractive index of hexane = 1.375
Refractive index of toulene = 1.497
Let mole fraction of hexane =
and, mole fraction of toulene =
Also, 
or, 
Hence, calculate the mole fraction of hexane as follows.
refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.
1.456 = 
1.456 = 
0.081 = 
= 
= 0.66
Since, 
= 1 - 0.66
= 0.34
Thus, we can conclude that mole fraction of hexane in your sample is 0.34.
The required amount of KClO₃ to prepare a saturated solution is 48 grams.
<h3>What is solubility?</h3>
The ability of a material, the solute, to create a solution with another substance, the solvent, is known as solubility.
Given graph is plotted between the temperature and solubility of the substance at 100g of water, so for the given points calculation will be:
- According to the graph for the KClO₃ we require almost 48g of KClO₃ to prepare a saturated solution.
- From the graph it is clear that at 40°C 40g of KCl will dissolve in 100g of water then amount of KCl which will dissolve in 68g of water will be calculated as:
x = (40)(68) / (100) = 27.2g
- On the basis of the graph, if 75 grams of calcium chloride is added to 100 g of water at 25°C then the obtained solution is the unsaturated as they have les solute then the limit.
- Based on the graph cerium sulfate behaves like a precipitate which will not dissolve at any temperature and present in the physical state.
- We can add more 30g to make the KCl solution saturated.
Hence, we require almost 48g of KClO₃ to prepare a saturated solution of KClO₃.
To know more about solubility, visit the below link:
brainly.com/question/16903071
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