The electric force between two charge objects is calculated through the Coulomb's law.
                               F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
                           2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m. 
        
                    
             
        
        
        
Answer:
 = 1.7 cm
 = 1.7 cm
Explanation:
The magnification of the compound microscope is given by the product of the magnification of each lens
         M = M₀  
         M = - L/f₀  25/
Where f₀ and  are the focal lengths of the lens and eyepiece, respectively, all values in centimeters
 are the focal lengths of the lens and eyepiece, respectively, all values in centimeters
In this exercise they give us the magnification (M = 400X), the focal length of the lens (f₀ = 0.6 cm), the distance of the tube (L = 16 cm), let's look for the focal length of the eyepiece ( )
)
           = - L / f₀ 25 / M
 = - L / f₀ 25 / M
Let's calculate
          = - 16 / 0.6 25 / (-400)
 = - 16 / 0.6 25 / (-400)
          = 1.67 cm
 = 1.67 cm
The minus sign in the magnification is because the image is inverted.
            = 1.7 cm
 = 1.7 cm
 
        
             
        
        
        
Answer:
A. ls sensitive to heat 
this is correct answer
I hope it's helpful for you.......