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saveliy_v [14]
4 years ago
7

field lines point out from all sides on a object. Some of the lines point into a second object nearby. Which statement best desc

ribes the objects? A. both objects are permanent magnets B. both objects are electromagnets C. the first object is negatively charged, and the second object is positively charged D. the first object is positively charged, and the second object is negatively charged
Physics
1 answer:
Klio2033 [76]4 years ago
4 0

Answer:

The first object is positively charged, and the second object is negatively charged. (D)

Explanation:

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A student walks 3 miles west and then 4 miles south to get to school the student displacement was
sattari [20]
Draw an x y axis

3 miles west is 3 miles to the left, -3
4 miles south is 4 miles down, -4

connect the the point to the origin, that side is what you are looking for 
that side is also hypotenus

using Pythagorean theorem

sqrt(-4^2 + 3^2)
sqrt(25)
5 

your displacement is 5

3 0
3 years ago
Which of the following processes occurs in the cells of plants?
Gnom [1K]

Answer:

A., B. & C.

Explanation:

All apply, because all these happen in a plant.

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3 years ago
The cephalocaudal trend can be described as the__________direction of motor development.
Sergio039 [100]
It is C i think it might be C
8 0
3 years ago
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.2, A car starting from rest has an acceleration of
riadik2000 [5.3K]

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

=  0 + 0.5 × 5

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s = ut + 1/2 at²

= 1/2 × 2.5 × 5

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7 0
4 years ago
It is 5.0 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10 km/h
Ostrovityanka [42]

Answer:

Walking burns up more energy,1740000J

Explanation:

Given that the displacement is 5.0km, and running at 10km/h and uses, walking at 3km/hr and uses 290watts:

Energy consumption for running is calculated as:

700watts=700j/s,d=5000m,v=\frac{25}{9}m/s\\\\\therefore E_c=\frac{d}{v}\times Energy \ usage\\\\=\frac{5000}{\frac{25}{9}}\times 700j/s\\\\=1260000J

Energy consumption for walking is calculated as:

290watts=290j/s,d=5000m,v=\frac{5}{6}m/s\\\\\therefore E_c=\frac{d}{v}\times Energy \ usage\\\\=\frac{5000}{\frac{5}{6}}\times 290j/s\\\\=1740000J

Walking is a slower process hence the need for more energy over longer periods  raltive to running the same distance.

Hence walking burns more energy; 1,740,000J. It burns more because you walk for a greater period of time.

5 0
3 years ago
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