1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
saveliy_v [14]
4 years ago
7

field lines point out from all sides on a object. Some of the lines point into a second object nearby. Which statement best desc

ribes the objects? A. both objects are permanent magnets B. both objects are electromagnets C. the first object is negatively charged, and the second object is positively charged D. the first object is positively charged, and the second object is negatively charged
Physics
1 answer:
Klio2033 [76]4 years ago
4 0

Answer:

The first object is positively charged, and the second object is negatively charged. (D)

Explanation:

You might be interested in
Un the way to the moon, the Apollo astro-
kherson [118]

Answer:

Distance =  345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2}  } \\

F_{m} =G*\frac{m_{m}*m_{a}  }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]

When we match these equations the masses cancel out as the universal gravitational constant

G*\frac{m_{e} *m_{a} }{r_{e}^{2}  } = G*\frac{m_{m} *m_{a} }{r_{m}^{2}  }\\\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2}  }

To solve this equation we have to replace the first equation of related with the distances.

\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m}  )^{2}  } = \frac{7.36*10^{22}  }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17}  \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c }  }{2*a}\\  where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) }  }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

<u>Second part</u>

<u />

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2}  } \\a=3.33*10^{19} [m/s^2]

6 0
3 years ago
What the planet after Venus
Aleonysh [2.5K]

Mercury and Venus are therefore closer to each other most of the time. But Earth is the planet closest to Venus. And that's why from here on Earth, Venus looks so big and luminous. Venus is the brightest thing in the night sky after the sun and the moon.

4 0
3 years ago
Read 2 more answers
Anyone good with scientific notations? I sure am not
defon
B is the answer that I know of.
7 0
3 years ago
Read 2 more answers
You are measuring the volume of a chemical beaker how would u take the measurment?
8090 [49]

I think its d  because lifting it would make the chemical swish around and that will make it so you cant get the right measurement. hope this helps :)

6 0
3 years ago
Which source is most likely an authority on the subject? Dr. Vale, a pediatrician, discusses electrical circuitry on her home-im
Naddika [18.5K]
The correct answer is Dr. Patel, a cardiologist, presents her findings on heart disease.

A cardiologist is a heart doctor, so he would be the highest authority to speak about heart disease. The others are all amateurs in their businesses.
6 0
4 years ago
Read 2 more answers
Other questions:
  • The potential difference between a pair of oppositely charged parallel plates is 398 V. If the spacing between the plates is dou
    14·1 answer
  • EXTREME HELP!!!!
    8·1 answer
  • An object falling. What type of energy is being described
    9·2 answers
  • Two spaceships leave Earth in opposite directions, each with a speed of 0.60c with respect to Earth. (a) What is the SPEED of sp
    14·1 answer
  • What is quantitative?
    8·1 answer
  • How much work must be done in the car to slow it from 100km/h to 50km/h
    15·1 answer
  • What has a positive charge a comb or rubber band?
    6·2 answers
  • Particles q1 = -53.0 uc, q2 = +105 uc, and
    7·1 answer
  • Two 6 ohm resistors in parallel gives an equivalent resistance of
    14·1 answer
  • What is Si system? Why has Si system been developed? Give reason.​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!