E = 0.5mv^2 = 0.5*44*10^2 = 2200J
An object in motion changes position
Answer:
Bounce 1 , pass 3, emb2
Explanation:
(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle. So it is Bounce1, pass3, emb2.
Answer:the will have the same acceleration
Explanation:according to fállelos theory they land at the same time
Answer:
unchanged
Explanation:
Let the voltage of the battery be V
Inductance L1 = 5 mH
Inductance L2 = 10 mH
consider resistance R of the circuit (wire, battery).
V = I R + L dI/dt
where, I is the current in the circuit and t is the time.
After few seconds of connection being made, the factor dI/dt is negligible. There is no change in the current flowing through the circuit. when inductor was just attached in the circuit, a current
