Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 320 N/C. (a) What is the ma
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The acceleration of the object if the net force is decreased = 0.13 m/s²
<h3>Further explanation</h3>Given
A net force of 0.8 N acting on a 1.5-kg mass.
The net force is decreased to 0.2 N
Required
The acceleration of the object if the net force is decreased
Solution
Newton's 2nd law :
The mass used in state 1 and 2 remains the same, at 1.5 kg
- state 1
ΣF=0.8 N
m=1.5 kg
The acceleration, a:
- state 2
ΣF=0.2 N
m=1.5 kg
The acceleration, a:
Answer:
0.021
Explanation:
The period of a pendulum is dependent on the length of the string holding the pendulum, L, and acceleration due to gravity, g. It is given mathematically as:
Let us make L the subject of the formula:
We are not told that the length of the string changes, hence, we can conclude that it is constant in both locations.
When the period of the pendulum is 2 s and the acceleration due to gravity is 9.8, the length L is:
When the pendulum is moved to a new location, the period becomes 1.99782 s.
We have concluded that length is constant, hence, we can find the new acceleration due to gravity, :
Therefore:
The difference between the new acceleration due to gravity, and the former acceleration due to gravity, g, will be:
=
=
The acceleration due to gravity differs by a value of at the new location.