The balanced reaction
is:
AgNO3 + NaCl = NaNO3 + AgCl
<span>We are given the amount of silver nitrate to react with sodium chloride. This
will be our starting point.</span>
15.0 mol AgNO3 (1 mol AgCl / 1
mol AgNO3 ) =15.0 mol AgCl
The amount of moles produced is the same with the amount of the given reactant since they only one is to one ratio.
So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
Was there supposed to be a picture?
Answer:
11
So, 1 mole of sucrose contains 12 moles of carbon atoms, 22 moles of hydrogen atoms, and 11 moles of oxygen atoms.
Explanation:
Mark Brainliest
In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N.
N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 = +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is = -3
