There are three which are:
dispersion/london/van der vaals forces
dipole/dipole
hydrogen bonding
<h2>Competitive inhibitors.</h2>
Explanation:
▪ Transition state analogs can be used as inhibitors in enzyme-catalyzed reactions which are done by blocking the active site of the enzyme.
▪ A transition state analog is somewhat the same as that of the transition state.
▪These are better inhibitors than the substrate analogs in competitive inhibition, the reason is that they bind tighter to the enzyme rather than the substrate.
▪ Thus, they are classified as competitive inhibitors.
The answer is Oxygen. The<span> elements that has the same lewis structure as sulfur is Oxygen. </span><span>This is due to the fact that although the two compounds have different electronic configurations, the two have the same arrangement of electrons in their outermost orbits. </span>
For 1 mole of any substance, there are 6.02214086 × 10^<span>23 particles (atoms, molecules, ions, etc. depending on the substance)
So, for 1 mole of water, there are </span>6.02214086 × 10^23 water particles, and so on
So, in 1 mole of Lithium, there are 6.02214086 × 10^23 Lithium atoms
Answer:
1.7 × 10 ^42
Explanation:
Using Nernst equation
E°cell = RT/nF Inq
at equilibrium
Q=K
E°cell = 0.0257 /n Ink= 0.0592/n log K
Fe2+(aq)+2e−→Fe(s) E∘= −0.45 V
Ag+aq)+e−→Ag(s) E∘= 0.80 V
Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)
balance the reaction
Fe → Fe²⁺ + 2e⁻ reversing for oxidation E° = 0.45 v
2 Ag⁺ +2e⁻ → 2Ag
n = 2 moles and K = equilibrium constant
E° cell = 0.80 + 0.45 = 1.25 V
E° cell = (0.0592 / n) log K
substitute the value into the equations and solve for K
(1.25 × 2) / 0.0592 = log K
42.23 = log K
k = 10^ 42.23
K = 1.7 × 10 ^42
