Answer:
c) a buffer solution with pH= 5
Explanation:
The equation of hydrolisis of water is:
1x10⁻¹⁴ = [H⁺] [OH⁻]
That means if we know [H⁺] we can find hydroxide-ion concentration and vice versa.
a) HCl 0.1M = [H⁺] = 0.1M;
1x10⁻¹⁴ / [H⁺]
1x10⁻¹⁴/ 0.1M = [OH⁻]
1x10⁻¹³M = [OH⁻] hydroxide- ion concentration.
b) 0.1M H₂SO₄ = 0.2M [H⁺]
1x10⁻¹⁴/ 0.2M = [OH⁻]
5x10⁻¹⁴M = [OH⁻]
c) pH = 5.
[H⁺] = 1x10⁻⁵M
1x10⁻¹⁴/ 1x10⁻⁵M = [OH⁻]
1x10⁻⁹M = [OH⁻]
d) pOH = 12.
[OH⁻] = 1x10⁻¹²M
That means risht answer is:
<h3>c) a buffer solution with pH= 5</h3>
Answer:
The answer is true
Explanation:
Products in chemical reactions are rearranged during the reaction, the atoms end up in different combinations in the products. This makes the product new substances that are chemically different than the reactants
Answer:
METHOD 1: (surface area of a solid reactant) METHOD 2: (concentration or pressure of a reactant)
Explanation:
METHOD 1: (surface area of a solid reactant) Increasing the surface area of a solid reactant exposes more of its particles to attack. This results in an increased chance of collisions between reactant particles, so there are more collisions in any given time and the rate of reaction increases.
METHOD 2: (concentration or pressure of a reactant) Increasing the concentration means that we have more particles in the same volume of solution. This increases the chance of collisions between reactant particles, resulting in more collisions in any given time and a faster reaction. As we increase the pressure of reacting gases, we increase the rate of reaction.
I thinlk it's by radiation?......
Answer:
NA = 6.8 E-12 Kg H2(g) / hour
Explanation:
steady-state diffusion of A through non-diffuser B:
- NA = (DAB/RTz)(p*A1 - p*A2)
∴ (A): H2(g)
∴ (B): Pd
∴ DAB = 1.7 E-8 m²/s
∴ p*A1 = 2.0 Kg H2 / m³ Pd
∴ p*A2 = 0.4 Kg H2 / m³ Pd
∴ z = 6 mm = 6 E-3 m
∴ T = 600°C ≅ 873 K
∴ R = 8.314 J/mol.K = 8.314 N.m/mol.K
⇒ NA = ((1.7 E-8)/(8.314)(873)(6 E-3))(2.0 - 0.4)
⇒ NA = 6.246 E-10 mol/s.m³
for A = 0.25 m²
⇒ volume (v) = A×z = (0.25)(6 E-3) = 1.5 E-3 m³
∴ Mw H2(g) = 2.016 g/mol
⇒ NA = (6.246 E-10 mol/s.m³)(1.5 E-3 m³)(2.016 g/mol)(Kg/1000 g)(3600 s/h)
⇒ NA = 6.8 E-12 Kg H2(g)/h
