Answer:
the resistance of the second wire is 1 ohm.
Explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝ 
Since the length of the two wires is constant
R₁A₁ = R₂A₂
Therefore, the resistance of the second wire is 1 ohm.
Since it moves 5 m/s faster every second, after 20 seconds it's moving 100 m/s faster than when it started speeding up.
If it was moving at 14 m/s when the acceleration began, it's moving at 114 m/s at the end of the 20 seconds. Its velocity is <em>114 m/s North.</em>
That's 255 mph !
D. How high do the sound waves go
B) The amount of work done
A front is defined as a "boundary" that separates two masses of different air densities. I am not entirely sure, but I think the answers are either C or D, but I'm mostly convinced it's option D.
