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Kipish [7]
2 years ago
13

A student solving a physics problem to find the unknown has applied physics principles and obtained the expression: μkmgcosθ=mgs

inθ−ma, where g=9.80meter/second2, a=3.60meter/second2, θ=27.0∘, and m is not given. Which of the following represents a simplified expression for μk?
tanθ− ag
To avoid making mistakes, the expression should not be simplified until the numerical values are substituted.
gsinθ−agcosθ
The single equation has two unknowns and cannot be solved with the information given.
Physics
1 answer:
BaLLatris [955]2 years ago
4 0

Answer:

\mu_k=\dfrac{gsin\theta -a}{gcos\theta}

Explanation:

g = Acceleration due to gravity = 9.80 m/s²

a = Acceleration= 3.6 m/s²

\theta = Angle = 27°

The equation is

\mu_kmgcos\theta=mgsin\theta -ma

Mass gets cancelled

\\\Rightarrow \mu_kgcos\theta=gsin\theta -a

Rearranging for \mu_k

\\\Rightarrow \mu_k=\dfrac{gsin\theta -a}{gcos\theta}

The simplified expression is

\mathbf{\mu_k=\dfrac{gsin\theta -a}{gcos\theta}}

*the options are incomplete. The above answer is the required solution

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Three beads are placed on the vertices of an equilateral triangle of side d = 3.4cm. The first bead of mass m1=140gis placed on
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Xcm = 1.95 cm  and Ycm = 1.76 cm

Explanation:

The very useful concept of mass center is

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Where ri, mi are the mass positions of the bodies from some reference point by selecting and M is the total mass of the body.

Let's look for the total mass

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Let's look for the position of each point

Point 1. top vertex, if the triangle has as side d

      R₁ = d / 2 i ^ + d j ^

      R₁ = (1.7 cm i ^ + 3.4 j ^) cm

Point 2. left vertex. What is the origin of the system?

      R₂ = 0

Point 3. Right vertex

      R₃ = d i ^

      R₃ = 3.4 i ^ cm

a) The x component of the massage center

      Xcm = 1 / M (m₁ x₁ + m₂ x₂ + m₃ x₃)

      Xcm = 1 / M (m₁ d / 2 + 0 + m₃ d)

      Xcm = d / M (m₁ / 2 + m₃)

b)   Let's write the mass center component x

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      Xcm = 238/270

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c) let's find the component and center of mass

     Ycm = 1 / M (m₁ y₁ + m₂ y₂ + m₃ y₃)

    Ycm = 1 / M (m₁ d + 0 + 0)

    Ycm = m₁ / M d

d) let's calculate

    Y cm = 1/270 (140 3.4 + 0 + 0)

    Ycm = 1.76 cm

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