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Kipish [7]
3 years ago
13

A student solving a physics problem to find the unknown has applied physics principles and obtained the expression: μkmgcosθ=mgs

inθ−ma, where g=9.80meter/second2, a=3.60meter/second2, θ=27.0∘, and m is not given. Which of the following represents a simplified expression for μk?
tanθ− ag
To avoid making mistakes, the expression should not be simplified until the numerical values are substituted.
gsinθ−agcosθ
The single equation has two unknowns and cannot be solved with the information given.
Physics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

\mu_k=\dfrac{gsin\theta -a}{gcos\theta}

Explanation:

g = Acceleration due to gravity = 9.80 m/s²

a = Acceleration= 3.6 m/s²

\theta = Angle = 27°

The equation is

\mu_kmgcos\theta=mgsin\theta -ma

Mass gets cancelled

\\\Rightarrow \mu_kgcos\theta=gsin\theta -a

Rearranging for \mu_k

\\\Rightarrow \mu_k=\dfrac{gsin\theta -a}{gcos\theta}

The simplified expression is

\mathbf{\mu_k=\dfrac{gsin\theta -a}{gcos\theta}}

*the options are incomplete. The above answer is the required solution

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Examine the symbols below:
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Answer: Symbol A

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The four symbols described here represent:

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The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60 cm ) sin ( 6.20 y+ 60.0 t ), where y is in m
trapecia [35]

Answer:

The question is incomplete, below is the complete question

"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.

A) What is the frequency of this wave?

B)  What is the wavelength of this wave?

C) What is the speed of this wave?"

Answers:

a.  f=\frac{30}{\pi }Hz\\

b. wavelength=\frac{\pi }{3.1}m \\

c. v=9.68m/s

Explanation:

The equation of a wave is represented as

D(x,t)=Asin(kx+wt) \\

Where A=amplitude

w=angular frequency=2πf

K=wave numbers =2π/λ

since we re giving he equation  D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),

we can compare and get the value for the wave number and angular frequency.

By comparing we have

w=60rads/s

k=6.20

a. to determine the frequency, from the expression fr angular wave frequency we have

w=2πf hence

f=w/2π

if we substitute we arrive at

f=\frac{60}{2\pi }\\f=\frac{30}{\pi }Hz\\

b. to determine the wave length, we use

k=\frac{2\pi }{wavelength} \\k=6.2\\wavelength=\frac{2\pi }{k} \\wavelength=\frac{2\pi }{6.2} \\wavelength=\frac{\pi }{3.1}m \\

c. the wave speed  v is express as the product of the frequency and the wavelength. Hence

v=frequency*wavelength \\v=\frac{30}{\pi } *\frac{\pi }{3.1}\\ v=9.68m/s

6 0
3 years ago
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