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Kipish [7]
3 years ago
13

A student solving a physics problem to find the unknown has applied physics principles and obtained the expression: μkmgcosθ=mgs

inθ−ma, where g=9.80meter/second2, a=3.60meter/second2, θ=27.0∘, and m is not given. Which of the following represents a simplified expression for μk?
tanθ− ag
To avoid making mistakes, the expression should not be simplified until the numerical values are substituted.
gsinθ−agcosθ
The single equation has two unknowns and cannot be solved with the information given.
Physics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

\mu_k=\dfrac{gsin\theta -a}{gcos\theta}

Explanation:

g = Acceleration due to gravity = 9.80 m/s²

a = Acceleration= 3.6 m/s²

\theta = Angle = 27°

The equation is

\mu_kmgcos\theta=mgsin\theta -ma

Mass gets cancelled

\\\Rightarrow \mu_kgcos\theta=gsin\theta -a

Rearranging for \mu_k

\\\Rightarrow \mu_k=\dfrac{gsin\theta -a}{gcos\theta}

The simplified expression is

\mathbf{\mu_k=\dfrac{gsin\theta -a}{gcos\theta}}

*the options are incomplete. The above answer is the required solution

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Answer:

Explanation:

1 )

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v2,f= (m2-m1)v2,i + 2m1v1,i/m1+m2

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v2,f =  2m1v1,i/m1+m2

In this equation coefficient of v1,i is positive so v2,f and v1,i have the same sign.

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Put m1 < m2  and v2,i =0 in first equation

v1,f= (m1-m2)v1,i + 2m2v2,1/m1+m2

v1,f= (m1-m2)v1,i

As m1-m2 is negative , v1f and v1i will have opposite sign.

3 )

Put m1 > m2  and v2,i =0 in first equation

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v1,f= (m1-m2)v1,i

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Put m1 = m2 and v2,i =0 in first equation

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