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REY [17]
2 years ago
14

What is the frequency of blue light that has a wavelength of 450 nm?

Physics
1 answer:
Gennadij [26K]2 years ago
8 0

Explanation:

The frequency of blue light that has a wavelength of 450 nm is 6.7×1014 6.7 × 10 14 Hz.

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The atomic number of a nucleus descended during which nuclear reactions?
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Answer:

(A.)Nuclear fission and beta decay (electron emission)

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In football we see unbalanced forces. When 1 player exerts an unbalanced force on another player and causes a player to
zaharov [31]

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Fall

Explanation:

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A sample of ice at 0°C has a mass of 23 g and a volume of 25 cm^3. Why does ice float on water? The density of water is 1 g.
vlabodo [156]

Answer: ice float in water due to density differences. Water has a higher density than ice.less dense object in liquid with high density

Explanation: from density formulae.

D=M/V

Density of ice =Mass of ice/Volume of ice

D=23/25

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3 years ago
Is corona the least dense layer in the sun? please fast
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Answer:

the Corona is about 10 million times less dense than sun's surface.this low density makesuch less bright than surface of the sun

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3 years ago
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A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the neg
Natali5045456 [20]

Answer: Vf = 2,400,000 m/s

Explanation:

1) The only relevant force is the electrostatic force

2) The formula for the electrostatic force is F = E×q

Where E is the electric field and q is the magnitude of the charge.

3) Since the electric field is the same in both cases, and the charge of the protons and electrons have the same magnitude, you can state that the magntitude of the electric forces acting in both proton and electron are the same

4) Fe = Fp (Fe stands for force on the electron and Fp stands for force on the proton).

5) Using second law of Newton, Force = mass × acceleration

Fe = Me × Ae (Me is mass of the electron, and Ae is acceleration of the electron)

Fp = Mp × Ap (Mp is mass of the proton, and Ap is acceleration of the proton)

⇒Me × Ae = Mp × Ap

⇒ Ae = Mp × Ap / Me

6) Now, state the equations for the velocity in uniformly accelerated motion:

i) Vf² = Vo² + 2ad

Vo² = 0 for both cases, and d is the same distance.

⇒ Vf² = 2ad

ii) For the proton Vf² = 2(Ap)(d) ⇒ Ap = Vf² / (2d)

⇒ Ap = (55,000 m/s)² / (2d)

iii) For the electron Vf² = 2(Ae)² (2d)

iv) Using Ae = Mp × Ap / Me (found prevously):

Vf² = Mp × (55,000 m/s)² / (2d) × (2d) / Me

⇒ Vf² = Mp × (55,000 m/s)² / Me

Taking square root in both sides:

⇒ Vf = 55,000 m/s × √ [Mp / Me]

7) These are the values for the masses of a proton and an electron:

Mp = 1.67 × 10⁻²⁷ kg

Me = 9.11×10⁻³¹ kg

8) Replace and compute:

Vf = 55,000 m/s × √ [ 1.67 × 10⁻²⁷ kg / 9.11×10⁻³¹ kg] = 2,354,841.8 m/s

Round to two significan digits: Vf = 2,400,000 m/s

5 0
3 years ago
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