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3 years ago

Use of force to move an object over a distance

Physics

1 answer:

MatroZZZ [7]3 years ago

5 0

Very interesting question. I would be happy to answer if it was actually, indeed, a question

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Which of these components is present in this circuit schematic?

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A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave

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Answer:

$\lambda$ = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = $n \times \frac{1}{4} \lambda$ ...............1

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$L = \frac{\lambda}{2} + \frac{\lambda}{4}\\$

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$\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}$

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3 years ago

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ytyug

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3 years ago

What is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of?

madreJ [45]

We will apply the Newton's second Law so the we will be able to find the acceleration.
F (tot) = ma
a = F(tot) / m
a = 32.0 N / 65.0 kg = 0.492 m/s^2
Approximately 0.492 m/s^2 is her initial acceleration if she is initially stationary and wearing steel-bladed skates.

7 0

3 years ago

3 نقطة (نقاط)

Molodets [167]

The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

$W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J$

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force <em>P</em>. Let $W_P$ be the work done by the force <em>P</em>. Then the total work done on the block is

$W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}$

5 0

3 years ago